ΔH증기가 액체에 대한 기화의 엔탈피인 경우, R은 가스 상수이며, A는 물질의 화학적 정체성에 따라 값이 일정한 다. 온도(T)는이방정식에서 켈빈에 있어야합니다. 그러나 증기 압력과 온도 간의 관계가 선형이 아니기 때문에 방정식은 선형 방정식을 산출하기 위해 로그리지믹 형태로 재배열되는 경우가 많습니다.어떤 액체의 경우, 특정 온도에서 기화 및 증기 압력의 엔탈피가 알려지면 클라우시우스-클랩페이론 방정식은 다른 온도에서 액체의 증기 압력을 결정할 수 있게 한다. 이렇게 하려면 선형 방정식이 2점 형식으로 표현될 수 있습니다. 온도 T1에서증기 압력은 P1이고온도 T2에서증기 압력은 P2이며,해당 선형 방정식은 다음과 같습니다.상수 A는동일하므로 이 두 방정식은 ln A를 격리한 다음 서로 동일하게 설정하도록 재배열될 수 있습니다." />

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11.9: 클라우지우스-클라페롱 식

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Clausius-Clapeyron Equation
 
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11.9: Clausius-Clapeyron Equation

The equilibrium between a liquid and its vapor depends on the temperature of the system; a rise in temperature causes a corresponding rise in the vapor pressure of its liquid. The Clausius-Clapeyron equation gives the quantitative relation between a substance’s vapor pressure (P) and its temperature (T); it predicts the rate at which vapor pressure increases per unit increase in temperature.

Eq1

where ΔHvap is the enthalpy of vaporization for the liquid, R is the gas constant, and A is a constant whose value depends on the chemical identity of the substance. Temperature (T) must be in kelvin in this equation. However, since the relationship between vapor pressure and temperature is not linear, the equation is often rearranged into logarithmic form to yield the linear equation:

Eq2

For any liquid, if the enthalpy of vaporization and vapor pressure at a particular temperature is known, the Clausius-Clapeyron equation allows to determine the liquid’s vapor pressure at a different temperature. To do this, the linear equation may be expressed in a two-point format. If at temperature T1, the vapor pressure is P1, and at temperature T2, the vapor pressure is P2, the corresponding linear equations are:

Eq3

Since the constant, A, is the same, these two equations may be rearranged to isolate ln A and then set them equal to one another:

Eq4

which can be combined into:

Eq5

This text is adapted from Openstax, Chemistry 2e, Section 10.3: Phase Transitions.

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