한편, 강한 염기는 수성 용액에서 완전히 해리되고 수산화 이온을 생성하는 화합물이다. 예를 들어, 그룹 1 금속 수산화물인 0.015 M KOH는 완전히 해리되고 0.015 M의OH및 0.015 M의 K+를생성한다.그룹 2 금속 수산화제는 수산화 바륨 [Ba(OH)2]및 수산화스트 [Sr(OH)2]와같이 강한 염기이며 2개의 수산화 이온을 가지고 있다. 이로 인해 동일한 농도에서 NaOH 또는 KOH에 비해 보다 기본적인 해결책을 생성하게 됩니다. 예를 들어 0.015 M Ba(OH)2는 0.015 M Ba+ 및 0.030 M 수산화를 생성합니다.강한 산과 염기가 완전히 해리됨에 따라, 어금니 비율은 하이드로늄 및 수산화 농도를 결정하는 데 사용될 수 있으며, 이는 차례로 용액의 pH 또는 pOH를 계산하는 데 사용할 수 있습니다. 예를 들어 0.030 M HCl 용액은 0.03 M 하이드로늄 이온을 생성합니다. 따라서이 솔루션의 pH는동일한 솔루션의 pOH는 수식을 사용하여 결정할 수…." />

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15.6: 강산 용액과 강염기 용액

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Strong Acid and Base Solutions
 
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15.6: Strong Acid and Base Solutions

A strong acid is a compound that dissociates completely in an aqueous solution and produces a concentration of hydronium ions equal to the initial concentration of acid. For example, 0.20 M hydrobromic acid will dissociate completely in water and produces 0.20 M of hydronium ions and 0.20 M of bromide ions.

Eq1

On the other hand, a strong base is a compound that dissociates completely in an aqueous solution and produces hydroxide ions. For example, 0.015 M KOH, a group 1 metal hydroxide, will dissociate completely and produce 0.015 M of OH- and 0.015 M of K+.

Eq2

Group 2 metal hydroxides, like barium hydroxide [Ba(OH)2] and strontium hydroxide [Sr(OH)2], are also strong bases and possess two hydroxide ions. This causes them to produce a more basic solution compared to NaOH or KOH at the same concentration. For example, 0.015 M Ba(OH)produces 0.015 M Baand 0.030 M hydroxide.

Eq3

As strong acids and bases dissociate completely, molar ratios can be used to determine their hydronium and hydroxide concentrations, which in turn can be used to calculate the pH or pOH of a solution. For example, a 0.030 M HCl solution will produce 0.03 M hydronium ions. Therefore the pH of this solution will be

Eq4

The pOH of the same solution can be determined using the formula

Eq5

As the pH of the solution is 1.52, its pOH can be calculated as

Eq6

Similarly, the concentration of hydroxide ions produced by strong bases can be used to determine the pOH of a solution using the equation

Eq7

The above equation can also be used to determine the hydroxide ion concentration when pOH is known. For example, if the pOH of a solution is 3.00,

Eq8

Multiplication of both sides by −1 gives

Eq9

Now, take the antilog of both sides

Eq10

Thus, the hydronium ion concentration of the solution with pOH 3 is 1.0 × 10−3 M. A similar method can be used to determine the hydronium ion concentration of a solution if its pH is known.

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Strong Acid Solutions Strong Base Solutions Dissociation Hydronium Ions Nitric Acid Nitrate Ions Concentration PH HCl Chloride Ions Logarithm Solution Concentration Hydronium Ion Concentration Antilog Group One Metal Hydroxides Sodium Hydroxide Potassium Hydroxide

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