Name: estimating function behavior with average value
Uploaded: 2026-01-12T12:24:45.000Z
Duration: 1 min 17 s
Channel: JoVE

القيمة المتوسطة لدالة على فترة مغلقة تعادل ارتفاع مستطيل مساحته تساوي مجموع المساحات الموجبة والسالبة تحت المنحنى.على سبيل المثال، خذ درجة الحرارة في بيت زجاجي مسجلة بشكل مستمر على مدى 24 ساعة.تتغير درجة الحرارة مع مرور الوقت، لكن قيمة واحدة تمثل متوسط درجة الحرارة.لحساب ذلك، يتم تقسيم الفترة إلى فترات فرعية صغيرة متساوية العرض. في كل فترة فرعية، تؤخذ قيمة دالة تمثيلية كارتفاع مستطيل رفيع. جمع مساحات جميع هذه المستطيلات يعطي تقديرا للمساحة تحت المنحنى.مع زيادة عدد الفترات الفرعية، تقترب هذه الطريقة من قيمة دقيقة تلتقط السلوك العام للدالة عبر الفترة.تؤدي هذه العملية إلى تعبير يتضمن تكاملا محددا. النتيجة تتوافق مع المساحة تحت منحنى الدالة، مقسومة على عرض المسافة.بالنسبة للدالة الموجبة، يفسر هذا على أنه ارتفاع مستطيل مساحته مساحته تحت المنحنى.

القيمة المتوسطة للدالة

Average Value of a Function

&#x64A;&#x645;&#x643;&#x646; &#x62A;&#x641;&#x633;&#x64A;&#x631; &#x627;&#x644;&#x642;&#x64A;&#x645;&#x629; &#x627;&#x644;&#x645;&#x62A;&#x648;&#x633;&#x637;&#x629; &#x644;&#x644;&#x62F;&#x627;&#x644;&#x629; &#x639;&#x644;&#x649; &#x641;&#x62A;&#x631;&#x629; &#x645;&#x63A;&#x644;&#x642;&#x629; &#x62A;&#x641;&#x633;&#x64A;&#x631;&#x64B;&#x627; &#x647;&#x646;&#x62F;&#x633;&#x64A;&#x64B;&#x627; &#x639;&#x644;&#x649; &#x623;&#x646;&#x647; &#x627;&#x631;&#x62A;&#x641;&#x627;&#x639; &#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644; &#x62A;&#x633;&#x627;&#x648;&#x64A; &#x645;&#x633;&#x627;&#x62D;&#x62A;&#x647; &#x627;&#x644;&#x645;&#x633;&#x627;&#x62D;&#x629; &#x627;&#x644;&#x635;&#x627;&#x641;&#x64A;&#x629; &#x627;&#x644;&#x648;&#x627;&#x642;&#x639;&#x629; &#x62A;&#x62D;&#x62A; &#x627;&#x644;&#x645;&#x646;&#x62D;&#x646;&#x649; &#x639;&#x644;&#x649; &#x62A;&#x644;&#x643; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x629;. &#x648;&#x62A;&#x631;&#x627;&#x639;&#x64A; &#x647;&#x630;&#x647; &#x627;&#x644;&#x645;&#x633;&#x627;&#x62D;&#x629; &#x627;&#x644;&#x635;&#x627;&#x641;&#x64A;&#x629; &#x625;&#x633;&#x647;&#x627;&#x645;&#x627;&#x62A; &#x627;&#x644;&#x62F;&#x627;&#x644;&#x629; &#x627;&#x644;&#x645;&#x648;&#x62C;&#x628;&#x629; &#x648;&#x627;&#x644;&#x633;&#x627;&#x644;&#x628;&#x629; &#x645;&#x639;&#x64B;&#x627;&#x60C; &#x645;&#x645;&#x627; &#x64A;&#x648;&#x641;&#x631; &#x642;&#x64A;&#x645;&#x629; &#x62A;&#x645;&#x62B;&#x64A;&#x644;&#x64A;&#x629; &#x648;&#x627;&#x62D;&#x62F;&#x629; &#x62A;&#x639;&#x643;&#x633; &#x627;&#x644;&#x633;&#x644;&#x648;&#x643; &#x627;&#x644;&#x639;&#x627;&#x645; &#x644;&#x644;&#x62F;&#x627;&#x644;&#x629;.\begin{equation*}f_{\text{avg}} = \jfrac{1}{b - a} \int_a^b f(x)\,dx\\end{equation*}&#x64A;&#x638;&#x647;&#x631; &#x645;&#x62B;&#x627;&#x644; &#x639;&#x645;&#x644;&#x64A; &#x644;&#x647;&#x630;&#x647; &#x627;&#x644;&#x641;&#x643;&#x631;&#x629; &#x639;&#x646;&#x62F; &#x645;&#x631;&#x627;&#x642;&#x628;&#x629; &#x62F;&#x631;&#x62C;&#x629; &#x627;&#x644;&#x62D;&#x631;&#x627;&#x631;&#x629; &#x62F;&#x627;&#x62E;&#x644; &#x62F;&#x641;&#x64A;&#x626;&#x629; &#x639;&#x644;&#x649; &#x645;&#x62F;&#x627;&#x631; 24 &#x633;&#x627;&#x639;&#x629;. &#x648;&#x639;&#x644;&#x649; &#x627;&#x644;&#x631;&#x63A;&#x645; &#x645;&#x646; &#x623;&#x646; &#x62F;&#x631;&#x62C;&#x629; &#x627;&#x644;&#x62D;&#x631;&#x627;&#x631;&#x629; &#x62A;&#x62A;&#x63A;&#x64A;&#x631; &#x628;&#x627;&#x633;&#x62A;&#x645;&#x631;&#x627;&#x631; &#x637;&#x648;&#x627;&#x644; &#x627;&#x644;&#x64A;&#x648;&#x645;&#x60C; &#x641;&#x625;&#x646;&#x647; &#x64A;&#x643;&#x648;&#x646; &#x645;&#x646; &#x627;&#x644;&#x645;&#x641;&#x64A;&#x62F; &#x63A;&#x627;&#x644;&#x628;&#x64B;&#x627; &#x62A;&#x644;&#x62E;&#x64A;&#x635; &#x647;&#x630;&#x627; &#x627;&#x644;&#x62A;&#x63A;&#x64A;&#x631; &#x628;&#x631;&#x642;&#x645; &#x648;&#x627;&#x62D;&#x62F; &#x64A;&#x645;&#x62B;&#x644; &#x645;&#x62A;&#x648;&#x633;&#x637; &#x62F;&#x631;&#x62C;&#x629; &#x627;&#x644;&#x62D;&#x631;&#x627;&#x631;&#x629; &#x639;&#x644;&#x649; &#x627;&#x645;&#x62A;&#x62F;&#x627;&#x62F; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x629; &#x627;&#x644;&#x632;&#x645;&#x646;&#x64A;&#x629; &#x628;&#x623;&#x643;&#x645;&#x644;&#x647;&#x627;.&#x648;&#x644;&#x625;&#x64A;&#x62C;&#x627;&#x62F; &#x647;&#x630;&#x627; &#x627;&#x644;&#x645;&#x62A;&#x648;&#x633;&#x637;&#x60C; &#x62A;&#x64F;&#x642;&#x633;&#x64E;&#x651;&#x645; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x629; &#x625;&#x644;&#x649; &#x639;&#x62F;&#x62F; &#x643;&#x628;&#x64A;&#x631; &#x645;&#x646; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x627;&#x62A; &#x627;&#x644;&#x641;&#x631;&#x639;&#x64A;&#x629; &#x627;&#x644;&#x635;&#x63A;&#x64A;&#x631;&#x629; &#x645;&#x62A;&#x633;&#x627;&#x648;&#x64A;&#x629; &#x627;&#x644;&#x639;&#x631;&#x636;. &#x648;&#x641;&#x64A; &#x643;&#x644; &#x641;&#x62A;&#x631;&#x629; &#x641;&#x631;&#x639;&#x64A;&#x629; &#x62A;&#x64F;&#x62E;&#x62A;&#x627;&#x631; &#x642;&#x64A;&#x645;&#x629; &#x645;&#x645;&#x62B;&#x644;&#x629; &#x644;&#x644;&#x62F;&#x627;&#x644;&#x629;&#x60C; &#x648;&#x62A;&#x64F;&#x62A;&#x62E;&#x630; &#x627;&#x631;&#x62A;&#x641;&#x627;&#x639;&#x64B;&#x627; &#x644;&#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644; &#x631;&#x641;&#x64A;&#x639;. &#x648;&#x62A;&#x642;&#x631;&#x650;&#x651;&#x628; &#x645;&#x633;&#x627;&#x62D;&#x629; &#x643;&#x644; &#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644; &#x625;&#x633;&#x647;&#x627;&#x645; &#x627;&#x644;&#x62F;&#x627;&#x644;&#x629; &#x62E;&#x644;&#x627;&#x644; &#x630;&#x644;&#x643; &#x627;&#x644;&#x62C;&#x632;&#x621; &#x627;&#x644;&#x642;&#x635;&#x64A;&#x631;. &#x648;&#x64A;&#x639;&#x637;&#x64A; &#x62C;&#x645;&#x639; &#x645;&#x633;&#x627;&#x62D;&#x627;&#x62A; &#x647;&#x630;&#x647; &#x627;&#x644;&#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644;&#x627;&#x62A; &#x643;&#x644;&#x647;&#x627; &#x62A;&#x642;&#x62F;&#x64A;&#x631;&#x64B;&#x627; &#x644;&#x644;&#x645;&#x633;&#x627;&#x62D;&#x629; &#x627;&#x644;&#x643;&#x644;&#x64A;&#x629; &#x62A;&#x62D;&#x62A; &#x627;&#x644;&#x645;&#x646;&#x62D;&#x646;&#x649;.&#x648;&#x645;&#x639; &#x627;&#x632;&#x62F;&#x64A;&#x627;&#x62F; &#x639;&#x62F;&#x62F; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x627;&#x62A; &#x627;&#x644;&#x641;&#x631;&#x639;&#x64A;&#x629; &#x648;&#x62A;&#x646;&#x627;&#x642;&#x635; &#x639;&#x631;&#x648;&#x636;&#x647;&#x627;&#x60C; &#x62A;&#x632;&#x62F;&#x627;&#x62F; &#x62F;&#x642;&#x629; &#x647;&#x630;&#x627; &#x627;&#x644;&#x62A;&#x642;&#x631;&#x64A;&#x628;. &#x648;&#x641;&#x64A; &#x627;&#x644;&#x62D;&#x627;&#x644;&#x629; &#x627;&#x644;&#x62D;&#x62F;&#x64A;&#x629;&#x60C; &#x64A;&#x62A;&#x642;&#x627;&#x631;&#x628; &#x645;&#x62C;&#x645;&#x648;&#x639; &#x645;&#x633;&#x627;&#x62D;&#x627;&#x62A; &#x627;&#x644;&#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644;&#x627;&#x62A; &#x625;&#x644;&#x649; &#x627;&#x644;&#x642;&#x64A;&#x645;&#x629; &#x627;&#x644;&#x62A;&#x631;&#x627;&#x643;&#x645;&#x64A;&#x629; &#x627;&#x644;&#x62F;&#x642;&#x64A;&#x642;&#x629; &#x644;&#x644;&#x62F;&#x627;&#x644;&#x629; &#x639;&#x644;&#x649; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x629;. &#x648;&#x62A;&#x62A;&#x648;&#x627;&#x641;&#x642; &#x647;&#x630;&#x647; &#x627;&#x644;&#x639;&#x645;&#x644;&#x64A;&#x629; &#x627;&#x644;&#x62D;&#x62F;&#x64A;&#x629; &#x645;&#x639; &#x627;&#x644;&#x62A;&#x643;&#x627;&#x645;&#x644; &#x627;&#x644;&#x645;&#x62D;&#x62F;&#x62F; &#x627;&#x644;&#x645;&#x648;&#x636;&#x62D; &#x623;&#x639;&#x644;&#x627;&#x647;.&#x648;&#x639;&#x646;&#x62F;&#x645;&#x627; &#x62A;&#x628;&#x642;&#x649; &#x627;&#x644;&#x62F;&#x627;&#x644;&#x629; &#x645;&#x648;&#x62C;&#x628;&#x629; &#x62A;&#x645;&#x627;&#x645;&#x64B;&#x627; &#x639;&#x644;&#x649; &#x627;&#x644;&#x641;&#x62A;&#x631;&#x629;&#x60C; &#x64A;&#x645;&#x643;&#x646; &#x62A;&#x635;&#x648;&#x631; &#x627;&#x644;&#x642;&#x64A;&#x645;&#x629; &#x627;&#x644;&#x645;&#x62A;&#x648;&#x633;&#x637;&#x629; &#x639;&#x644;&#x649; &#x623;&#x646;&#x647;&#x627; &#x627;&#x631;&#x62A;&#x641;&#x627;&#x639; &#x645;&#x633;&#x62A;&#x637;&#x64A;&#x644; &#x62A;&#x62A;&#x637;&#x627;&#x628;&#x642; &#x645;&#x633;&#x627;&#x62D;&#x62A;&#x647; &#x645;&#x639; &#x627;&#x644;&#x645;&#x633;&#x627;&#x62D;&#x629; &#x627;&#x644;&#x648;&#x627;&#x642;&#x639;&#x629; &#x62A;&#x62D;&#x62A; &#x627;&#x644;&#x645;&#x646;&#x62D;&#x646;&#x649;. &#x648;&#x64A;&#x648;&#x641;&#x631; &#x647;&#x630;&#x627; &#x627;&#x644;&#x62A;&#x641;&#x633;&#x64A;&#x631; &#x627;&#x644;&#x647;&#x646;&#x62F;&#x633;&#x64A; &#x641;&#x647;&#x645;&#x64B;&#x627; &#x648;&#x627;&#x636;&#x62D;&#x64B;&#x627; &#x648;&#x628;&#x62F;&#x64A;&#x647;&#x64A;&#x64B;&#x627; &#x644;&#x643;&#x64A;&#x641;&#x64A;&#x629; &#x62A;&#x644;&#x62E;&#x64A;&#x635; &#x627;&#x644;&#x642;&#x64A;&#x645;&#x629; &#x627;&#x644;&#x645;&#x62A;&#x648;&#x633;&#x637;&#x629; &#x644;&#x633;&#x644;&#x648;&#x643; &#x643;&#x645;&#x64A;&#x629; &#x62A;&#x62A;&#x63A;&#x64A;&#x631; &#x62A;&#x63A;&#x64A;&#x631;&#x64B;&#x627; &#x645;&#x633;&#x62A;&#x645;&#x631;&#x64B;&#x627;.

&#x64A;&#x645;&#x643;&#x646; &#x62A;&#x641;&#x633;&#x64A;&#x631; &#x627;&#x644;&#x642;&#x64A;&#x645;&#x629; ...

Education

JoVE Core

Calculus

حساب التفاضل والتكامل

Unit

وحدة

Applications of Integration

تطبيقات التكامل

KEY TERMS AND CONCEPTS

المصطلحات والمفاهيم الأساسية

estimating function behavior with average value

The average value of a function gives one number that summarizes how a quantity changes over a closed interval. It can also be viewed as the height of a rectangle whose area matches the net area under the curve. That net area includes both positive and negative parts of the function, so the result reflects the function’s overall behavior.

A greenhouse temperature over a 24-hour period is a practical example of this idea. The temperature may rise and fall throughout the day, but it is still useful to describe it with a single average temperature for the full time interval. To estimate that value, the interval is divided into many small subintervals of equal width.

On each small piece, a representative function value is chosen. That value becomes the height of a thin rectangle. The area of each rectangle estimates the contribution of the function over that short interval, and adding all the rectangle areas gives an estimate of the total area under the curve.

As the number of subintervals increases and the widths get smaller, the estimate becomes more accurate. In the limit, the rectangular sum approaches the exact accumulated value of the function over the interval. This limiting process is the definite integral shown above.

When the function stays positive on the interval, the average value can be pictured more simply. It is the height of a rectangle with the same area as the region under the curve. This geometric view makes it easier to understand how average value condenses a changing quantity into one representative number.

Estimating Function Behavior with Average Value

estimating-function-behavior-with-average-value

area between curves: integrating with respect to x

area-between-curves-integrating-with-respect-to-x

Vertical Slices for Area Between Curves

Area between curves can be found by using vertical slices and a definite integral. For two continuous functions on a closed interval from a to b, the region is bounded by their graphs on the sides and by the interval endpoints across the bottom and top edges of the setup. A first estimate comes from splitting the interval into many narrow vertical strips of equal width. Each strip is treated like a rectangle. Its height is the vertical difference between the two functions at a chosen point...

area between curves: integrating with respect to y

area-between-curves-integrating-with-respect-to-y

Horizontal Slices for Area Between Curves

Area between curves can be found with horizontal slices when both boundaries are written as functions of y. The left and right curves are continuous from y = c to y = d, and those lines set the vertical limits of the region. Because the curves depend on y, the area is best measured by moving across the shape with thin horizontal strips. The method uses a Riemann sum. The region is divided into many thin strips with the same height, delta y. For each strip, the width is the horizontal distance...

area between curves: problem solving

Piecewise Area Between Curves

Piecewise area between curves uses more than one integral to find the size of a region on a graph. In this example, the region is enclosed by a square root function, a reflected cube root function, and a linear function. The line intersects each of the other two curves, and those intersection points show where the boundary of the region changes. The area cannot be found with one setup over the full interval because the top and bottom curves are not the same everywhere. The region is split at...

calculation of volume of solids by integration

calculation-of-volume-of-solids-by-integration

Slicing Methods for Solid Volume

Slicing methods help find the volume of solids with changing cross-sections. A basic solid, like a rectangular box, is easy to measure because its base area stays the same along its height. Many real objects do not have that regular shape, so elementary geometry is not enough. The slicing method solves this by breaking a solid into many very thin slices. These slices are taken perpendicular to a chosen axis, often the x-axis. Each slice has a small thickness, written as delta x, and a...

volumes of solids of revolution

Disk Method for Rotated Region Volume

The disk method is used to find the volume of a solid formed by rotating a region around an axis. The region is first drawn in a two-dimensional plane. When that region spins around a fixed line, called the axis of revolution, it creates a three-dimensional shape with rotational symmetry. These shapes appear often in math models, physics, and engineering. When the region touches the axis of revolution, the solid has no hollow space inside. Its cross-sections are circular, so the shape can be...

finding volume using cross-sectional area

finding-volume-using-cross-sectional-area

Tetrahedron Volume from Triangle Slices

Tetrahedron volume can be found by adding the areas of triangular slices. This method uses cross-sectional area, which is the area of a flat slice taken through a 3D solid. It is useful when a solid changes shape in a regular way and a simple geometric formula is not available. A tetrahedron is a good example. It has a height h and an equilateral triangle base with side length a. The coordinate system places the origin at the top vertex, and the y-axis goes downward along the height to the...

problem solving: volume

Finding the Volume of a Jet Fuel Tank

The volume of a jet fuel tank can be found with solids of revolution. The tank is modeled by rotating a two-dimensional region around the x-axis. This creates a three-dimensional shape that is symmetric about the axis of rotation. The region runs from 0 to 2 meters, so the tank’s shape can be measured along that length. Because the boundary curve touches the axis, the disk method works well here. The disk method breaks the solid into many very thin circular slices that are perpendicular to the...

average value of a function

The average value of a function gives one number that summarizes how a quantity changes over a closed interval. It can also be viewed as the height of a rectangle whose area matches the net area under the curve. That net area includes both positive and negative parts of the function, so the result reflects the function’s overall behavior. A greenhouse temperature over a 24-hour period is a practical example of this idea. The temperature may rise and fall throughout the day, but it is still...

key terms and concepts

Learn how the average value of a function is found with rectangles and definite integrals, using a greenhouse temperature example over a 24-hour period.

Estimating Function Behavior with Average Value | JoVE K12

The JoVE Core Calculus collection provides a comprehensive visual guide to the entire calculus sequence, seamlessly connecting mathematical theory to real-world applications in physics and economics. Through dynamic animated lessons, the course transitions smoothly from foundational single-variable concepts to advanced multivariable topics. Students will explore everything from standard differentiation and integration to spatial vectors, multi-dimensional derivatives, and complex vector fields. By breaking down abstract coordinate systems, infinite series, and spatial motion, this structured approach builds the robust analytical skills and advanced mastery essential for STEM success.

Estimating Function Behavior with Average Value

Description

Transcript