Name: hydraulic hoist force analysis
Uploaded: 2023-09-22T11:49:25.000Z
Duration: 1 min 26 s
Channel: JoVE

Considera un paranco idraulico che supporta un carico.
Assumendo una rappresentazione schematica semplificata di questa struttura del telaio, quale forza agisce sulle aste BD e BF, a condizione che le dimensioni delle aste e il peso del carico siano noti?
Qui, BF e BD sono due membri della forza, mentre EFG e EDC sono membri multi-forza.
Viene disegnato un diagramma di corpo libero per l'EFG dell'asta che indica tutte le forze.
Le componenti verticale e orizzontale della forza FBF possono essere espresse utilizzando un triangolo di pendenza.
La condizione di equilibrio del momento al giunto E dà la forza F BF .
Quindi, applicando la condizione di equilibrio della forza orizzontale al giunto E, viene valutata la forza di reazione orizzontale in E.
Allo stesso modo, la condizione di equilibrio della forza verticale fornisce la forza di reazione verticale al giunto E.
Ora, disegnando un diagramma di corpo libero per l'EDC dell'asta, le componenti della forza lungo BD possono essere espresse utilizzando un altro triangolo di pendenza.
Applicando la condizione di equilibrio del momento nel punto C, viene calcolata la forza F BD.

<ol>
	<li>Hibbeler, R.C. (2016). Ingegneria Meccanica \u2012 Statica e Dinamica. Hoboken, New Jersey: Pearson Prentice Hall. Pagine 305.</li>
	<li>Birra, F.P.; Johnston, E.R.; Mazurek, D.F; Cromwell, P.J. e Self, B.P. (2019). Meccanica vettoriale per ingegneri \u2012 Statica e dinamica. New York: McGraw-Hill. pagine 330</li>
	<li>Meriam, JL, Kraige, LG e Bolton, JN (2020). Ingegneria Meccanica \u2012 Statica. Hoboken, New Jersey: John Wiley. pagine 200</li>
</ol>

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telai: risoluzione dei problemi ii

Considera un sollevatore idraulico che supporta un carico di 1 kN. Supponendo una rappresentazione schematica semplificata di questa struttura a telaio, è possibile determinare la forza agente sui membri BD e BF. <img alt="Figure 1" src="/files/ftp_upload/14292/14292_PT_Fig_1v2.svg" style="text-align: center; height: 350px;" />

Le dimensioni dei membri e il peso del carico sono parametri noti. Questa struttura può essere considerata un telaio con BF e BD che agiscono come membri a due forze, mentre EFG e EDC sono membri a molte forze.

Viene considerato un diagramma di corpo libero per il membro EFG. La forza inclinata FBF può essere scomposta nelle componenti verticale ed orizzontale. La condizione di equilibrio del momento viene applicata all'articolazione E.

<img alt="Equation 1" src="/files/ftp_upload/14292/14292_PT_Equation_1v2.svg" style="text-align: center; height: 15px;" />

La forza FBF viene calcolata essere di 1.546 kN. Poi, viene applicata la condizione di equilibrio della forza orizzontale all'articolazione E.

<img alt="Equation 2" src="/files/ftp_upload/14292/14292_PT_Equation_2v2.svg" style="text-align: center; height: 15px;" />

Sostituendo il valore della componente orizzontale di FBF nell'equazione di equilibrio, la forza reattiva orizzontale in E viene calcolata come 0.375 kN. Allo stesso modo, viene applicata la condizione di equilibrio della forza verticale.

<img alt="Equation 3" src="/files/ftp_upload/14292/14292_PT_Equation_3v2.svg" style="text-align: center; height: 15px;" />

La forza reattiva verticale calcolata all'articolazione E è di 0.500 kN.

Ora, viene considerato un diagramma di corpo libero per il membro EDC. Le componenti orizzontali e verticali di FBD possono essere espresse utilizzando un triangolo di pendenza. Viene applicata la condizione di equilibrio del momento al punto C.

<img alt="Equation 4" src="/files/ftp_upload/14292/14292_PT_Equation_4v2.svg" style="text-align: center; height: 15px;" />

La forza F_BD viene calcolata pari a 1.677 kN.

Telai: Risoluzione dei problemi II

Si consideri un paranco idraulico che supporta un carico di 1 kN. Assumendo una rappresentazione schematica semplificata di questa struttura del telaio, la forza che agisce su BD e ...

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Frames: Problem Solving II

hydraulic hoist force analysis

Hydraulic hoist force analysis shows how to find the forces in key members of a simple frame. The load is 1 kN, and the structure is represented with known member dimensions. In this setup, BF and BD act as two-force members. EFG and EDC are multi-force members, so each one is analyzed with a free-body diagram.

The first step is to study member EFG. The inclined force in BF is split into vertical and horizontal parts. Then the moment equilibrium condition is applied at joint E. Using this step, the force in BF is found to be 1.546 kN.

Next, the horizontal force equilibrium at joint E is used. The horizontal part of the BF force is substituted into the equation. This gives the horizontal reaction force at E as 0.375 kN. The vertical force equilibrium at the same joint is also applied. The vertical reaction force at E is calculated as 0.500 kN.

A free-body diagram for member EDC is then considered. The horizontal and vertical parts of FBD are written using a slope triangle. Finally, the moment equilibrium condition at point C is applied. This calculation gives the force in BD as 1.677 kN.

Hydraulic Hoist Force Analysis

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Hydraulic hoist force analysis shows how to find the forces in key members of a simple frame. The load is 1 kN, and the structure is represented with known member dimensions. In this setup, BF and BD act as two-force members. EFG and EDC are multi-force members, so each one is analyzed with a free-body diagram. The first step is to study member EFG. The inclined force in BF is split into vertical and horizontal parts. Then the moment equilibrium condition is applied at joint E. Using this...

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key terms and concepts

Analyze a hydraulic hoist frame with free-body diagrams, equilibrium equations, and two-force members to find forces in BF, BD, and reactions at E.

Hydraulic Hoist Force Analysis | JoVE K12

JoVE Core Mechanical Engineering offers concise, easy-to-understand animated videos covering key topics such as equilibrium, forces, truss analysis, and structural mechanics. Explore their real-world applications, and witness these concepts in action through scientist-led experiments.

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Hydraulic Hoist Force Analysis

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