Name: truss force analysis at joints a to e
Uploaded: 2023-09-22T11:49:24.000Z
Duration: 1 min 30 s
Channel: JoVE

Bir duvara sabitlenmiş sürtünmesiz bağlantılara ve zeminde makara desteğine sahip bir kafes yapı düşünün. A eklemine 150 N'luk bir kuvvet uygulanırsa, kafes kirişin her bir elemanındaki kuvvetleri belirleyin.
Her bir eklemdeki kuvvetler, eklem yöntemi kullanılarak belirlenebilir.
İlk olarak, AC ve AB elemanları arasındaki açı, BC ve AB'nin uzunluk oranının tan tersi olarak belirlenebilir.
İkinci olarak, eklem A'nın serbest cisim diyagramını çizin ve kuvvetleri bileşenlerine ayırın. Denge denklemleri uygulanarak bilinmeyen kuvvetler belirlenebilir.
Daha sonra, B ve C eklemlerinin serbest cisim diyagramlarını çizerek ve denge denklemlerini kullanarak, B ve C eklemlerindeki bilinmeyen kuvvetler belirlenebilir.
Son olarak, D ve E eklemlerinin serbest cisim diyagramını çizin. CD ve EF üyeleri için, kuvvetleri yatay ve dikey bileşenlere çözün. D ve E eklemlerindeki bilinmeyen kuvvetler denge denklemleri kullanılarak belirlenebilir.

<ol>
	<li>Hibbeler, R.C. (2016). Mühendislik Mekaniği \u2012 Statik ve Dinamik. Hoboken, New Jersey: Pearson Prentice Salonu. sayfa 276-277.</li>
</ol>

Herhangi bir çıkar çatışması beyan edilmedi.

düğüm yöntemi: problem Çözme ii

Duvara ve rulo desteğine sabitlenmiş sürtünmesiz bir eklemi olan bir kiriş yapısı düşünün. Eğer 150 N kuvveti Ekleme A'ya uygulanırsa, kirişin her bir elemanındaki kuvvetler joints metodunu kullanarak belirlenebilir.

<img alt="Figure 1" src="/files/ftp_upload/14283/14283_PT_Fig_1v2.svg" style="text-align: center; height: 350px;" />

AC ve AB elemanları arasındaki açı, BC ve AB uzunluklarının oranının ters tanjantı alınarak bulunabilir ve elde edilen sonuç 67.38Â° olur. Joint A'nın serbest cisim diyagramı düşünülür ve tüm bilinmeyen kuvvetler bileşenlerine ayrılır.

Dik kuvvet dengesi koşulu, CA elemanına etki eden kuvveti hesaplamak için kullanılabilir ve bu değer 173.08 N'ye eşittir.

<img alt="Equation 1" src="/files/ftp_upload/14283/14283_PT_Equation_1v2.svg" style="text-align: center; height: 15px;" />

Benzer şekilde, yatay kuvvet denge koşulu, FAB kuvvetini 161.54 N olarak bulmak için kullanılabilir.

<img alt="Equation 2" src="/files/ftp_upload/14283/14283_PT_Equation_2v2.svg" style="text-align: center; height: 15px;" />

Joint B ve C'nin serbest cisim diyagramları düşünülür ve bilinmeyen kuvvetler FBD , FCD ve FEC için dikey ve yatay kuvvet denge koşulları uygulanır. Bu şekilde elde edilen değerler FBD , FCD , ve FEC için sırasıyla 161.53 N, 173.08 N ve 207.70 N'dir. 

Son olarak, Joint D ve E'nin serbest cisim diyagramları düşünülür ve dikey ve yatay kuvvet denge koşulları uygulanır. Bu, FED ve FDF değerlerini sırasıyla 138.46 N ve 265.39 N olarak verir.

Düğüm Yöntemi: Problem Çözme II

Bir duvara ve makara desteğine sabitlenmiş sürtünmesiz bağlantılara sahip bir kafes yapı düşünün. A eklemine 150 N'luk bir kuvvet uygulanırsa, her birindeki kuvvetler ...

Education

JoVE Core

Mechanical Engineering

Makine Mühendisliği

Unit 1

Ünite 1

Structural Analysis

Yapısal Analiz

KEY TERMS AND CONCEPTS

TEMEL TERİMLER VE KAVRAMLAR

Method of Joints: Problem Solving II

truss force analysis at joints a to e

Truss force analysis at joints A to E uses the method of joints to find the force in each member. The truss has frictionless joints, a wall support, and a roller support. A 150 N force is applied at joint A, and the member forces are solved from joint to joint.

First, the angle between members AC and AB is found using the inverse tangent of the ratio of BC to AB. This gives an angle of 67.38°. A free-body diagram of joint A is then drawn, and each unknown force is split into vertical and horizontal components.

The vertical force equilibrium equation is used to find the force in member CA, which is 173.08 N. The horizontal force equilibrium equation gives the force in member AB as 161.54 N. Free-body diagrams for joints B and C are then used to continue the calculation.

At joints B and C, the vertical and horizontal equilibrium conditions are applied again. This gives FBD = 161.53 N, FCD = 173.08 N, and FEC = 207.70 N. Free-body diagrams of joints D and E are used last, and the same equilibrium steps give FED = 138.46 N and FDF = 265.39 N.

Truss Force Analysis at Joints A to E

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machines

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key terms and concepts

Use the method of joints to solve truss forces at joints A to E. Find member forces from free-body diagrams, angles, and equilibrium equations.

Truss Force Analysis at Joints A to E | JoVE K12

JoVE Core Makine Mühendisliği, denge, kuvvetler, kafes kiriş analizi ve yapısal mekanik gibi temel konuları kapsayan kısa, anlaşılması kolay animasyonlu videolar sunar. Gerçek dünyadaki uygulamalarını keşfedin ve bilim insanlarının önderlik ettiği deneylerle bu kavramların uygulanmasına tanık olun.

mechanical engineering

Truss Force Analysis at Joints A to E

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