Name: truss member force analysis by sections
Uploaded: 2025-05-22T09:06:03.000Z
Duration: 1 min 30 s
Channel: JoVE

Duvara sabitlenmiş diyagonal, dikey ve yatay elemanlardan oluşan keyfi bir kafes yapı düşünün.
Kesitler yöntemi, CB, GB ve GH elemanlarına etki eden kuvveti hesaplamak için kullanılabilir.
Burada yatay ve düşey elemanların yükleri ve uzunlukları bilinen parametrelerdir.
CB, GB ve GH elemanlarını kesiştiren bir düzlem boyunca bir kesim yapılır ve sağ taraftaki bölümün serbest cisim diyagramı çizilir.
G noktası etrafındaki moment denge denklemi, CB boyunca kuvveti verir. Pozitif işaret, elemandaki gerilimi gösterir. 
Şimdi, FGB, BCG'de bir eğim üçgeni kullanılarak ifade edilebilirken, FGH, CEG'de bir eğim üçgeni kullanılarak ifade edilebilir.
Düşey ve yatay kuvvetlerin toplamı göz önüne alındığında kuvvet dengesi denklemleri yazılabilir.
FCB'nin değeri ikame edilir. Kuvvet denge denklemleri, GH ve GB elemanları boyunca kuvveti elde etmek için aynı anda çözülür.
FGH'nin negatif işareti kuvvetin sıkıştırıcı olduğunu gösterirken, FGB için pozitif işaret çekme kuvvetini gösterir.

<ol>
	<li>R. C., Hibbeler Mühendislik Mekaniği Statiği, Pearson. sayfa 291-293</li>
	<li>F.P. Beer, E.R. Johnston, D.F. Mazurek, P.J. Cornwell, B.P. Self, Mühendisler İçin Vektör Mekaniği Statik ve Dinamik Mühendislik Mekaniği Statiği, Mc Graw-Hill Eğitim. Sayfa 217</li>
</ol>

Herhangi bir çıkar çatışması beyan edilmedi.

kesit yöntemi: problem Çözme ii

Diyagonal, dikey ve yatay elemanlardan oluşan bir duvara sabitlenmiş keyfi bir kiriş yapısı düşünelim. Elemanlar CB, GB ve GH üzerinde etki eden kuvvetleri hesaplamak için kesit yöntemi kullanılabilir. Yatay ve dikey elemanların yükleri ve uzunlukları görselde gösterildiği gibi bilinen parametrelerdir.

<img alt="Figure 1" src="/files/ftp_upload/14287/14287_PT_Fig_1v2.svg" style="text-align: center; height: 350px;" />

Başlamak için, CB, GB ve GH elemanlarını kesen bir düzlem boyunca bir kesik yapılır ve sağ taraftaki kesitinin serbest cisim diyagramı çizilir.

<img alt="Figure 2" src="/files/ftp_upload/14287/14287_PT_Fig_2v2.svg" style="text-align: center; height: 350px;" />

G noktası etrafındaki moment dengesi denklemi uygulanır.

<img alt="Equation 1" src="/files/ftp_upload/14287/14287_PT_Equation_1v2.svg" style="text-align: center; height: 13px;" />

Sonuç, CB elemanındaki kuvveti 4 kN olarak ve pozitif işaretin elemanda gerilim olduğunu gösterir.

Şimdi, FCB CBG'inde eğim üçgeni kullanılarak ifade edilebilirken, FGH CEG'inde eğim üçgeni kullanılarak ifade edilebilir. Dikey ve yatay kuvvetlerin toplamı göz önüne alındığında, kuvvet dengesi denklemleri aşağıdaki gibi yazılabilir:

<img alt="Equation 2" src="/files/ftp_upload/14287/14287_PT_Equation_2v2.svg" style="text-align: center; height: 15px;" />

<img alt="Equation 3" src="/files/ftp_upload/14287/14287_PT_Equation_3v2.svg" style="text-align: center; height: 13px;" />

FCB denkleme yerleştirilir ve kuvvet dengesi denklemleri eşzamanlı olarak çözülür. Sonuçta, FGH kuvveti -7.454 kN ve FGB kuvveti 3.772 kN olarak bulunur. FGH'nin negatif işareti, kuvvetin sıkıştırma olduğunu, FGB'nin pozitif işareti ise çekme kuvvetini gösterir.

Kesit Yöntemi: Problem Çözme II

Duvara sabitlenmiş diyagonal, dikey ve yatay elemanlardan oluşan keyfi bir kafes yapı düşünün. Üyelere etki eden kuvveti hesaplamak için ...

Education

JoVE Core

Mechanical Engineering

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Unit 1

Ünite 1

Structural Analysis

Yapısal Analiz

KEY TERMS AND CONCEPTS

TEMEL TERİMLER VE KAVRAMLAR

Method of Sections: Problem Solving II

truss member force analysis by sections

Truss member force analysis by sections finds the forces in selected members of a wall-mounted truss. The structure here includes diagonal, vertical, and horizontal members. The known loads and member lengths are used to solve for the forces in CB, GB, and GH.

A cut is made through members CB, GB, and GH. The right side of the truss is then isolated as a free-body diagram. Next, the moment equilibrium equation is taken about point G. This step gives the force in member CB as 4 kN, and the positive sign shows that CB is in tension.

The force in CB is then written with a slope triangle in triangle BCG. The force in GH is written with a slope triangle in triangle CEG. After that, the sums of vertical and horizontal forces are set equal to zero. The equation for CB is substituted, and the remaining equations are solved at the same time.

The final values are FGH = -7.454 kN and FGB = 3.772 kN. The negative sign for GH means the member is in compression. The positive sign for GB means the member is in tension.

Truss Member Force Analysis by Sections

truss-force-analysis-using-method-of-sections

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Truss member force analysis by sections finds the forces in selected members of a wall-mounted truss. The structure here includes diagonal, vertical, and horizontal members. The known loads and member lengths are used to solve for the forces in CB, GB, and GH. A cut is made through members CB, GB, and GH. The right side of the truss is then isolated as a free-body diagram. Next, the moment equilibrium equation is taken about point G. This step gives the force in member CB as 4 kN, and the...

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key terms and concepts

Learn how the method of sections isolates a truss cut, uses moment and force balance, and identifies tension or compression in members CB, GB, and GH.

Truss Member Force Analysis by Sections | JoVE K12

JoVE Core Makine Mühendisliği, denge, kuvvetler, kafes kiriş analizi ve yapısal mekanik gibi temel konuları kapsayan kısa, anlaşılması kolay animasyonlu videolar sunar. Gerçek dünyadaki uygulamalarını keşfedin ve bilim insanlarının önderlik ettiği deneylerle bu kavramların uygulanmasına tanık olun.

mechanical engineering

Truss Member Force Analysis by Sections

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