Question 1

What products form when primary and secondary allylic alcohols are oxidized by manganese dioxide?

Accepted Answer

Primary allylic alcohols are oxidized to aldehydes, while secondary allylic alcohols form ketones. This selective oxidation occurs via a radical intermediate mechanism when activated manganese(IV) dioxide accepts electrons from the allylic carbon. The type of product depends on the substitution pattern of the starting alcohol.

Question 2

How is activated manganese(IV) dioxide prepared from manganese sulfate?

Accepted Answer

Activated MnO2 is prepared through a redox reaction between a Mn(II) salt, such as manganese sulfate, and potassium permanganate under either alkaline or acidic conditions. The mixture is then thoroughly dried to remove water, which competes with alcohol for active sites on the MnO2 surface, ensuring effective oxidation.

Question 3

Why does manganese dioxide selectively oxidize allylic and benzylic alcohols over other alcohols?

Accepted Answer

The selectivity arises from the stability of the allylic or benzylic carbon radical intermediate formed during oxidation. This radical is resonance-stabilized, increasing the rate of hydrogen atom transfer from the allylic or benzylic carbon. Non-allylic and non-benzylic alcohols form less stable radicals, making their oxidation much slower and leaving them unaffected.

Question 4

What is the first step in the radical oxidation mechanism of allylic alcohols?

Accepted Answer

The hydroxyl group of the alcohol initially adds to MnO2 to form an ester intermediate. This ester formation positions the alcohol for the subsequent electron transfer and hydrogen atom abstraction that generates the allylic or benzylic carbon radical.

Question 5

How does the manganese oxidation state change during the radical oxidation of allylic alcohols?

Accepted Answer

Mn(IV) is first reduced to Mn(III) when it accepts an electron and a hydrogen atom is transferred from the allylic carbon, forming the carbon radical. Further electron rearrangement then reduces Mn(III) to Mn(II), completing the catalytic cycle and forming the aldehyde or ketone product.

Question 6

Why must water be removed during the preparation and use of activated manganese(IV) dioxide?

Accepted Answer

Water competes with alcohol for the active sites on the MnO2 surface, reducing the availability of sites for alcohol oxidation. Thorough drying ensures that the alcohol substrate can effectively access the oxidizing sites on the MnO2, maximizing reaction efficiency and selectivity.

Question 7

What happens to non-benzylic alcohols when exposed to activated manganese(IV) dioxide?

Accepted Answer

Non-benzylic and non-allylic alcohols remain unaffected during radical oxidation by MnO2. Because these alcohols cannot form resonance-stabilized carbon radicals, the oxidation pathway is energetically unfavorable, and the reagent does not oxidize them under the reaction conditions.

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