8.6
تخيل إلكتروليتا ثنائيا AB بتركيز 'c' يتفكك بشكل عكسي إلى أيوناته المكونة. درجة هذا التفكك تمثل ب ⍺. هذا يعني أن تركيز التوازن لكل نوع أيوني يمكن التعب…
استنادا إلى نظرية آرينيوس في التفكك الكهربائي، يفسر قانون التخفيف لأوستوالد التوازن في المحاليل الإلكتروليتية المائية.
تخيل إلكتروليت AB بتركيز 'c' مول لكل لتر، والذي يتفكك بشكل عكسي إلى أيونات.
إذا كانت α هي درجة التفكك، فإن كل أيون له تركيز توازن cα، بينما النسبة غير المفكككة (1 − α) لها تركيز c(1 − α). تعرف هذه المصطلحات ثابت التوازن K، ويسمى ثابت التفكك.
قانون التخفيف لأوستوالد ينطبق فقط على الإلكتروليتات الضعيفة مثل حمض الخليك وNH₄OH.
الإلكتروليتات القوية مثل HCl و NaF تكون مفككة تقريبا بالكامل، مع اقتراب α من واحد. تحت هذه الشروط، يقترب (1 − α) من الصفر، مما يجعل القانون غير صالح رياضيا.
ينشأ فشل قانون الإلكتروليتات القوية لأن ثابت الماء العازل العالي عند الذوبان يضعف القوى الكهروستاتيكية، مما يؤدي إلى تفكك شبه كامل. وبالتالي، لا يوجد توازن بين الأيونات والجزيء، ويصبح قانون التخفيف لأوستوالد غير قابل للتطبيق.
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Q1: What is Ostwald's dilution law and how does it relate to electrolyte dissociation?
Ostwald's dilution law explains equilibrium in aqueous electrolyte solutions based on Arrhenius' theory of electrolytic dissociation. For an electrolyte AB at concentration c, the dissociation constant K equals cα²/(1−α), where α is the degree of dissociation. This law describes how weak electrolytes like acetic acid and NH₄OH reversibly dissociate into ions at equilibrium.
Q2: Why does Ostwald's dilution law fail for strong electrolytes?
Strong electrolytes like HCl and NaF are almost completely dissociated, with α approaching one, making (1−α) approach zero. This renders the law mathematically invalid. Water's high dielectric constant weakens electrostatic forces, causing near-complete dissociation and eliminating the ion-molecule equilibrium that the law requires.
Q3: How do you calculate equilibrium concentrations using the degree of dissociation?
For an electrolyte AB with concentration c and degree of dissociation α, each ion has equilibrium concentration cα, while the undissociated fraction has concentration c(1−α). These concentrations define the dissociation constant K, which governs the equilibrium state of weak electrolyte solutions.
Q4: What is the difference between weak and strong electrolytes in terms of dissociation?
Weak electrolytes like acetic acid partially dissociate, with α significantly less than one, allowing Ostwald's dilution law to apply. Strong electrolytes like NaCl and NaF are electrovalent compounds formed by electron transfer; they dissociate almost completely with α near one, making the law inapplicable to them.
Q5: How does the dielectric constant of a solvent affect electrolyte dissociation?
According to Coulomb's law, the dielectric constant of the medium affects electrostatic force strength and conductivity. Water's high dielectric constant weakens electrostatic forces between ions, promoting near-complete dissociation of strong electrolytes and enabling ion mobility for electrical conduction in solutions.
Q6: What is the simplified form of Ostwald's dilution law for very weak electrolytes?
For very weak electrolytes where α is much less than one, the term (1−α) approximates to one. The dissociation constant simplifies to K ≈ cα², making calculations more straightforward for solutions with minimal dissociation and allowing easier prediction of equilibrium behavior.
Q7: What structural difference exists between strong electrolytes and weak electrolytes?
Strong electrolytes like NaCl and NaF are electrovalent compounds composed solely of ions in their crystal structure, not molecules. When dissolved in water, these ions gain mobility and conduct electricity. Weak electrolytes exist as molecules that partially dissociate into ions upon dissolution in solution.