4.5
在溶剂有一定的量时,可以加入不同的溶质数来创造不同的溶液浓度。在稀释的浓度中,溶质的比例 相对溶剂来说就较少;而高浓度的 比例就较高。而溶液的浓度被表示为莫耳浓度 也就是在每公升溶液 中溶质的莫耳数。在这个式子里,分母是溶液的量 而不是溶剂的量。因此,要产出一公升一莫耳的溶液,一莫耳的溶质就会被加进容量瓶中,再加入一公升的 溶剂。相同的,一莫耳的溶质加进容量瓶中 再加入0.5公升的溶剂 就会产生两莫耳的溶液。不仅如此,莫耳浓度可以 用来作为溶质莫耳 数和溶液数的转换系数。举237公克的高锰酸钾 要被溶解在水中要做3莫耳的溶液为例。为了去计算整体的溶液体积,首先,溶质的重量必须转换成莫耳数。接着莫耳数会被分割成莫耳浓度 来得到0.5公升的体积。当水被多加时,溶液的体积总和增加 但溶质莫耳数 保持一致。这表示溶液浓度 就相对减少了,换句话说,溶液被稀释了。稀释浓缩或是原液,指的是溶液会在稀释前 后会被用与溶液的体积和 莫耳数相关的稀释等式来达成。M1跟V1是 一开始高浓度溶液的莫耳数和体积,M2和V2则是 最终稀释浓度的莫耳数和体积。举例来说,稀释等式 可以被用来准备高锰酸钾溶液,也就是所谓一 般的药用消毒剂 那么,如果要准备一公升0.2莫耳的的高 锰酸钾溶液需要多少体积的2莫耳原液? 因为我们知道M1、M2跟V2,那在用稀释等式计算V1的值后得到0.1公升。因此,0.1公升的原液会被加进 容量瓶中,再加入溶剂来制造 1公升0.2莫耳浓度的溶液。当溶液被稀释时,尽管浓度变了,但高锰酸钾的莫耳数 会维持一致。
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Q1: What is molarity and how is it calculated?
Molarity (M) is the number of moles of solute per liter of solution, expressed in mol/L. To calculate molarity, divide the moles of solute by the total volume of solution in liters. For example, dissolving 1 mole of solute in a volumetric flask and filling to the 1-liter mark creates a 1-molar solution. The key is using the total solution volume, not just the solvent volume, since solutes can affect the overall volume.
Q2: Why is the total solution volume used in the molarity equation instead of solvent volume?
The total solution volume is used because solutes can change the volume of a solution depending on their interactions with the solvent. Using solvent volume alone would give an inaccurate concentration. The molarity equation accounts for this by including the combined volume of both solute and solvent, ensuring precise concentration measurements for chemical reactions in aqueous solutions.
Q3: How do you prepare a solution of specific molarity using a volumetric flask?
To prepare a solution of specific molarity, add the calculated moles of solute to a volumetric flask, then add solvent until the liquid reaches the marked line for your desired volume. For instance, to make 1 liter of a 1-molar solution, add 1 mole of solute and fill to the 1-liter mark. This ensures the total solution volume equals your target volume and produces the correct concentration.
Q4: What happens to the number of moles of solute when a solution is diluted?
The number of moles of solute remains constant during dilution. When solvent is added to a concentrated solution, the total volume increases but the amount of solute stays the same, causing the concentration to decrease. This principle is expressed mathematically as M1V1 = M2V2, where the product of molarity and volume equals moles before and after dilution.
Q5: How do you use the dilution equation to prepare a dilute solution from a stock solution?
The dilution equation M1V1 = M2V2 relates the molarity and volume of a stock solution to the desired dilute solution. Identify the known values: M1 and V1 from the stock solution, M2 and V2 from your target solution. Solve for the unknown variable, typically V1, to determine how much stock solution to transfer to a new flask, then add solvent to reach the final volume.
Q6: What is the difference between a dilute and concentrated solution?
A dilute solution has a small proportion of solute relative to solvent, resulting in low concentration. A concentrated solution has a large proportion of solute relative to solvent, resulting in high concentration. Concentrated solutions, called stock solutions, are often stored in laboratories and diluted as needed to create solutions of lower concentrations for specific applications.
Q7: Can you convert between mass of solute and solution volume using molarity?
Yes, molarity serves as a conversion factor between moles of solute and solution volume. First convert mass to moles using molar mass, then use molarity to find volume by dividing moles by molarity. For example, 237 grams of potassium permanganate converted to moles, then divided by 3 M, yields 0.5 liters of solution. This allows precise preparation of solutions with known concentrations.