9.10
亚硝酸盐− (NO2 μ m) 的路易斯结构实际上可以通过两种不同的方式绘制,区别于 N-O 和 N=O 键的位置。
如果亚硝酸盐确实含有一个和一个双键,则两个键长度预期会有所不同。 两个原子之间的双键比同一两个原子之间的单个键更短 (更强)。 但是,实验表明, NO2−中的两个 N – O 键的强…
大多数分子和离子可以 使用独特的路易斯结构表示。但是,某些化合物可以通过 多个同等有效的路易斯结构表示。比如说三氧化硫的路易斯结构。每个氧原子和中心硫原子之间的单键 满足氧原子的八隅体要求。但是,为了使硫达成完整的八隅体状态,硫原子和一个氧原子之间必须形成 一个额外的键。由于三个氧中的任何一个均可与硫形成 双键,因此可绘制出三种不同的路易斯结构。这些路易斯结构 被称为共振结构,其中骨架结构 保持相同,但电子分布不同。这三种结构都是分子的有效和等价表示形式,但它们在自然界中并不存在。实际结构不会在这些共振结构之间振荡,而是三个路易斯结构的混合或平均,它可以用键长来测量。在亚硫酸盐中,硫-氧单键的长度 为 1.51 埃,而在三氧化硫中,硫-氧单键的长度为 1.42 埃。因此,在混杂分子中,键长 介于单键键长和双键键长之间。在混杂分子中,参与 双键或孤对的电子通常 离域在多个键或原子上,这意味着电子不是固定在一个特定原子上。离域化降低了电子的潜在能量 从而导致结构更稳定,被称为共振稳定。芳香族化合物也可以观察到共振现象 例如苯。苯是一个六边形碳环,每个碳原子键合有一个氢,并且碳原子之间交替存在 单键和双键。根据碳-碳双键的位置,苯可有两种共振结构。大家回想一下,双键通常 比单键短。然而,苯中所有的碳-碳键 具有相等的键长,它 介于碳-碳单键键长和双键键长 之间。因此,苯以共振杂化的形式存在 并且可以表示为内部带有一个圆圈的六边形。圆圈表示苯是两个共振结构 的混合物,双键不能 定域于任何两个特定的碳原子上。
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Q1: What are resonance structures and why do molecules have multiple Lewis representations?
Resonance structures are multiple, equally valid Lewis structures for a single molecule where the skeletal arrangement remains identical but electrons distribute differently. Certain compounds like sulfur trioxide and nitrite ions cannot be accurately represented by a single Lewis structure. Instead, two or more resonance forms are needed to describe the actual electron distribution. These structures are not interchangeable; the molecule exists as a resonance hybrid, an average of all possible structures.
Q2: How does a resonance hybrid differ from the individual resonance structures?
A resonance hybrid is the actual electronic structure of a molecule, representing an average of all resonance forms rather than oscillating between them. Individual resonance structures are convenient, imaginary representations used to describe bonding. The hybrid never possesses the electronic structure of any single resonance form. Like a rhinoceros is neither a dragon nor a unicorn, a resonance hybrid is neither of its resonance forms at any given time, yet it is a real entity confirmed by experimental evidence.
Q3: What does electron delocalization mean in resonance hybrid molecules?
Electron delocalization occurs when electrons participating in double bonds or lone pairs are not stationary on one particular atom but spread across multiple bonds or atoms. This distribution reduces the potential energy of electrons, resulting in resonance stabilization that makes the molecule more stable. In sulfur trioxide, electrons are delocalized across the sulfur-oxygen bonds, creating intermediate bond lengths between single and double bonds rather than distinct bond types.
Q4: Why do resonance hybrid molecules have intermediate bond lengths?
In resonance hybrids, bond lengths are intermediate between single and double bonds because electrons are delocalized across multiple bonding positions. For example, sulfur-oxygen bonds in sulfur trioxide measure 1.42 angstroms, between a typical single bond (1.51 angstroms) and a double bond. Similarly, all carbon-carbon bonds in benzene are equal and intermediate in length, confirming that the molecule exists as a hybrid rather than alternating single and double bonds.
Q5: How is benzene represented as a resonance hybrid?
Benzene is a hexagonal carbon ring with alternating single and double bonds between carbons. However, since all carbon-carbon bonds have equal lengths intermediate between single and double bonds, benzene cannot be represented by either resonance structure alone. Instead, benzene is depicted as a hexagon with a circle inside, indicating it is a blend of two resonance structures where double bonds cannot be localized to specific carbon atoms.
Q6: What experimental evidence confirms that molecules are resonance hybrids rather than oscillating structures?
Experimental measurements of bond lengths and bond strengths provide direct evidence for resonance hybrids. In nitrite ions and carbonate ions, all bonds are experimentally identical in length and strength, even though resonance structures suggest different bond types. If molecules oscillated between resonance forms, bonds would show different properties. Instead, the uniform measurements confirm that molecules exist as stable averages of resonance structures, not as fluctuating entities.
Q7: Why is resonance stabilization important for molecular stability?
Resonance stabilization lowers the potential energy of electrons through delocalization across multiple atoms or bonds, making resonance hybrid molecules more stable than any single resonance structure would predict. This energy reduction explains why molecules like benzene and carbonate ions are particularly stable and unreactive. The delocalized electron distribution provides greater stability than if electrons were confined to specific bonds, as shown in individual Lewis structures.