19.4
计算质量和实验测量质量之间的差异被称为原子质量缺陷。 对于氦 -4 ,质量缺陷表明质量“损失”为 4.0331 amu – 4.0026 amu = 0.0305 amu。 质子,中子和电子形成原子所导致的质量损失是由于该质量转换为能量 (随着原子形成而演变) 所致。 核结合能是原子核的核粒子结合在…
核稳定性最好用 核结合能来量化。考虑氦-4 原子,它有 两个质子、两个中子和两个电子。这些粒子已知质量的总和 比中性氦-4 的测量质量 大 0.0305 个原子质量单位。计算得出的原子质量与实验测量的原子质量 之间的差异称为质量亏损。氦-4 在形成过程中 释放出大量能量 是造成这种差异的原因。爱因斯坦的质能方程有助于估算 与质量损失相关的能量变化。把质量换算成千克,然后求解这个方程,结果以基本国际标准单位焦耳表示。显而易见,巨大的能量 伴随着微小的质量变化。核子结合在一起时所释放的能量 与把原子核分解成质子和中子 所需的能量相同,称为核结合能。对于氦,核结合能为每摩尔 2.74 万亿焦耳。除以阿伏伽德罗数,得到的 核结合能为每个氦核 4.55 皮焦耳。这也经常用电子伏来表示。对于氦-4,这相当于 每个原子核 28.4 兆电子伏。除以核子数 4,得到每个核子的核结合能。每个核子的核结合能 与质量数的关系图描述了 核素的相对稳定性。质量数在 40-100 之间的元素 的每核子结合能最高,铁-56 的每核子质量最低。为了获得稳定性,重核 倾向于通过称为裂变的 放热过程分裂为中型核,而轻核则通过聚变过程结合在一起。
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Q1: What is mass defect and why does it occur in atoms?
Mass defect is the difference between the calculated sum of individual particle masses and the experimentally measured atomic mass. In helium-4, this difference is 0.0305 atomic mass units. The mass defect occurs because mass converts to energy during nucleus formation, as described by Einstein's mass-energy equivalence equation E = mc².
Q2: How is nuclear binding energy calculated from mass defect?
Nuclear binding energy is calculated by converting the mass defect to kilograms and applying Einstein's equation E = mc², where c is the speed of light. For helium-4, the mass defect of 0.0305 grams per mole converts to 3.05 × 10⁻⁵ kilograms per mole, yielding a binding energy of 2.74 terajoules per mole.
Q3: What does binding energy per nucleon tell us about nuclear stability?
Binding energy per nucleon measures the average energy holding each nucleon in the nucleus and indicates relative nuclear stability. Elements with mass numbers between 40 and 100 have the highest binding energy per nucleon, with iron-56 being most stable. Higher binding energy per nucleon correlates with greater nuclear stability.
Q4: Why are electronvolts commonly used to express nuclear binding energy?
Electronvolts (eV) are convenient units for nuclear binding energy because they represent the energy scale of nuclear processes. One electronvolt equals 1.602 × 10⁻¹⁹ joules. Helium-4's binding energy of 28.4 megaelectronvolts per nucleus is more practical to express in eV than in joules.
Q5: How do heavy and light nuclei achieve stability differently?
Heavy nuclei achieve stability through nuclear fission, fragmenting into midsize nuclei in an exothermic process. Lighter nuclei achieve stability through nuclear fusion, combining to form larger nuclei. Both processes release energy because midsize nuclei have the highest binding energy per nucleon.
Q6: What is the relationship between mass and energy in nuclear reactions?
Nuclear reactions convert mass directly into energy through Einstein's mass-energy equivalence, E = mc². The energy changes in nuclear reactions are vastly greater than in chemical reactions because even tiny mass changes produce enormous energy. This principle explains why nuclear binding energy is so substantial compared to chemical bond energies.
Q7: How do you convert binding energy from molar to per-nucleus values?
Binding energy per nucleus is calculated by dividing the molar binding energy by Avogadro's number (6.022 × 10²³). For helium-4, the molar binding energy of 2.74 terajoules per mole divided by Avogadro's number yields 4.55 picojoules per nucleus, or 28.4 megaelectronvolts per nucleus.