确定率法律和秩序的反应

All chemical reactions have a specific rate, which defines how quickly the reactants turn into products.

Chemical reactions are governed by two factors: kinetics and thermodynamics. Thermodynamic factors account for whether or not a reaction will occur, and if it absorbs or gives off energy during the process.

Kinetics refers to the rate of a chemical reaction, and how fast the system reaches equilibrium. The kinetics of a reaction is described by the kinetic rate law, which defines the rate based on a reaction rate constant, the concentration of components, and the order of the reaction.

This video will introduce reaction kinetics using the rate law equation, and will demonstrate how to determine the rate law for a certain reaction in the laboratory.

For a general reaction, the reaction rate equals the rate constant times the concentrations of the reactants, each raised to a reaction order. The rate constant, k, is fixed for a reaction at a given temperature.

The reaction orders are independent of the stoichiometric coefficients. Instead they are dependent on the reaction mechanism, and illustrate how the rate is related to the concentration of reactants. For example, if the reaction rate is unchanged when the concentration of “A” doubles, then the reaction does not depend on concentration, and the order is zero.

If the rate doubles when the concentration of reactant “A” doubles, then the reaction is first order with respect to “A.” The same behavior is true for reactant “B”. The overall order of a reaction is the sum of the individual reaction orders for each reactant.

During a reaction, the concentration of reactants changes with time. Note that that the basic rate equation does not include time as a variable, and can only relate rate and concentration at a specific time point. However, the rate changes as the reaction proceeds and as reactants are depleted. Using a differential rate law can relate the change in concentration to time.

The rate law for a reaction must be determined experimentally, where a chemical reaction is carefully controlled at a constant temperature, and the concentration of the reactants or products measured at specific time intervals. Since concentration measurements are made at discrete time points, the differential rate law is difficult to correlate to experimental data.

Integrating the differential rate law results in a simpler equation, called the integrated rate law. The integrated rate law compares the reactant concentrations at the start of the reaction and at a specified time.

The integrated rate law equation varies depending on the order of the reaction. These equations can take the linear form y=mx+b. Thus, a plot of concentration vs time yields a linear plot for a zero order equation, a plot of the natural log of concentration vs time yields a linear plot for a first order equation, and so on. By fitting experimental data to these equations, the order of a reaction can be easily determined. The rate constant, k, can then be determined using the slope of the line. Finally, the units of k vary depending on the order of the reaction. For a zero order reaction, the units are moles per liter per second, for a first order reaction, the units are inverse seconds and for a second order reaction the units are liter per mole per second.

Now that the basics of kinetic rate laws have been explained, lets take a look at how to experimentally determine the rate law for the decomposition of hydrogen peroxide to water and oxygen.

In this experiment, the catalytic decomposition of hydrogen peroxide over a platinum catalyst is explored.

First, prepare 5 dilutions of hydrogen peroxide, as shown in the table. In this case, concentrations range from 0.882 – 0.176 M, using a 3% or 0.882 M stock solution. Allow the solutions to equilibrate to room temperature.

Next, prepare the reaction vessel using a test tube. First determine the volume by filling a large test tube to the top with water. Then, insert a 1-hole rubber stopper until it is tight and water pushes out of the hole through the top.

Remove the stopper, and pour the water into a graduated cylinder to measure the exact volume. This is the volume of the reaction vessel.

Next, pour 50 mL of the first hydrogen peroxide solution into the test tube, and then place the tube in the 25 °C water bath. Once equilibrated, add a platinum coated reaction disc, and seal the system with a stopper connected to a gas pressure sensor.

Since one of the products is oxygen gas, the increase of pressure in the system is used to measure the increase in oxygen. Set up the pressure sensor to acquire data at 2 points per s, then run the experiment for 120 s. Bubbles should be visible as the peroxide decomposes to oxygen gas and water.

When the reaction period is over, release the pressure and dispose of the peroxide solution. Rinse the tube, then fill the tube with the next hydrogen peroxide solution. Repeat the gas pressure measurement for all solutions.

Plot the pressure versus time data for each solution. The pressure of evolved oxygen is directly proportional to the moles of oxygen formed according to the ideal gas law. Following the chemical reaction, the moles of oxygen formed can be used to calculate the moles of decomposed hydrogen peroxide. First, assume that the concentration of hydrogen peroxide did not change significantly during the short duration of the experiment. Thus, the plotted data represents only the initial region of the kinetics experiment.

Determine the slope of each data set using a linear regression. The slope is equal to the initial reaction rate in units of pressure of oxygen per second.

Next, plot of the natural log of the initial reaction rate vs the natural log of initial peroxide concentration. The slope is equal to the reaction order, m, and is approximately equal to one. Therefore, the reaction is first order.

The rate for each trial is in units of pressure in Torr, per second. To determine the rate constant, first convert the rate to units of atmospheres per second. Because the bubbles evolved in the aqueous solution, subtract the vapor pressure of water from the system pressure for each trial. The new rate then only reflects the pressure due to oxygen evolution.

Apply the ideal gas law to convert the rate from atmospheres per se to moles per s for each trial. Two times the moles of oxygen produced are equal to the moles of hydrogen peroxide decomposed, according to the chemical reaction stoichiometry. Then, use the reaction volume to convert the units of the rate to molarity per second.

Determine the rate constants for each trial by dividing the rate in molarity per s by the initial concentration. In this experiment, the average rate constant, k, is approximately 1.48 x 10-4 per s. The reaction is first order, known from the natural log – natural log plot shown earlier. Therefore, the rate law can be written as shown.

Now that you’ve looked at how to determine the rate law for a chemical reaction, lets look at some areas where this concept is applied.

Chemical reactions are used in the synthesis of compounds and materials used in a wide range of scientific applications. It is important to understand the reaction rate in these synthesis steps, in order to control the progress of a reaction.

For example, the synthesis of cadmium selenide nanocrystals and nanorods proceeds through a series of chemical reactions. Each reaction has its own discrete reaction rate, and therefore synthesis step is carefully controlled based on the knowledge speed of the reaction; some slow and some very quick.

The reaction rate law can also be used to describe radioactive decay, and determine the half-life of radioactive material. Half-life refers to the amount of time required for the concentration of a material to fall to half of its initial concentration.

Radioactivity follows first order kinetics, meaning that the time required for radioactive material to decay to a safe level can be very well characterized, enabling proper transport and storage of radioactive material and radioactive waste.

Similar to radioactive materials, drugs also have a half-life and degrade in the body. For example, some drugs have high rate constants, meaning that they degrade quickly, and must be taken frequently. Knowledge of this degradation rate enables the determination of the appropriate dosage, usage and delivery method.

You’ve just watched JoVE’s introduction to reaction rates. You should now understand the different orders of chemical reactions, how they relate to chemical reaction rates, and how to determine the rate law for a given chemical reaction in the laboratory.

Thanks for watching!