11.6
回転運動の仕事と動力は、並進運動の仕事と動力に完全に類似しています。 固定軸を中心に剛体を角度'' 回転させるために行われる仕事の合計は、角変位にわたって積分されたトルクの合計です。 したがって、回転運動におけるトルクと角変位は、それぞれ並進運動における力と直線変位に似ています。
同様に、固定軸の周…
池の水車を考えてみましょう。パイプから落下する水は、位置ベクトルで角度Φを作る力を水車に及ぼし、次に、小さな角度dθで車輪を回転させる力によって行われる仕事は、FsinΦdsです。
アーク ds は r に dθ を掛けたものに等しいため、行われる作業は FsinΦ と rdθ の積です。
トルクの大きさはrFsinΦに等しいことを思い出してください。 したがって、代入すると、行われた作業の式は τ に dθ を掛けたものに等しくなります。
一般に、剛体がθ1からθ2に回転する場合、体に対して行われる総仕事は、正味トルクと角変位の積分に等しくなります。
力によって供給される瞬間的な力は、一定のトルクを持つ固定軸を中心に物体を回転させる力によって作業が行われる速度です。したがって、電力はτ×dθ/dtで表されます。dθ/dtはホイールの角速度ωであるため、パワーはトルクと角速度の積に等しくなります。
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Q1: How is work calculated in rotational motion?
Work in rotational motion is calculated as the product of torque and angular displacement. When a rigid body rotates through a small angle dθ, the work done equals torque times dθ. For rotation from angle θ1 to θ2, total work is the integration of net torque over the angular displacement, analogous to force times displacement in translational motion.
Q2: What is the relationship between torque, angular velocity, and power?
Power in rotational motion equals torque multiplied by angular velocity. Since angular velocity is the rate of change of angular displacement (dθ/dt), instantaneous power represents the rate at which work is done by a force rotating an object about a fixed axis. This relationship mirrors the translational power formula of force times velocity.
Q3: Why does applying force at a distance from the axis matter for rotating objects?
Applying force at a distance from the central axis generates torque, which determines the power delivered to a rotating system. The farther the force is applied from the axis, the greater the torque produced for the same force magnitude. Since power depends on torque and angular velocity, the distance from the axis directly affects how efficiently work is done on rotating objects like a merry-go-round.
Q4: How does the waterwheel example demonstrate work in rotational motion?
In a waterwheel, falling water exerts a force at an angle to the position vector. The component of force perpendicular to the radius (FsinΦ) creates torque. As the wheel rotates through angle dθ, work done equals this torque component times the angular displacement, illustrating how force, distance, and angle combine to produce rotational work.
Q5: What are the SI units for work and power in rotational systems?
Work in rotational motion is measured in joules, the same unit as translational work. Power is measured in watts, equivalent to joules per second. These SI units apply universally to rotational systems because work and power in rotational motion are completely analogous to their translational counterparts.
Q6: How does the work-energy theorem apply to rotating rigid bodies?
The work-energy theorem for rotational motion states that total work done on a rigid body equals the change in its rotational kinetic energy. Since work is calculated as the integral of net torque over angular displacement, this theorem connects the torque applied to a body with its resulting angular acceleration and energy changes.
Q7: What is the key analogy between rotational and translational motion for work and power?
In rotational motion, torque and angular displacement are analogous to force and linear displacement in translational motion. Similarly, power in rotation equals torque times angular velocity, just as translational power equals force times velocity. This complete analogy means the mathematical relationships and physical principles governing work and power are identical in both systems.