20.18
立体化学は、特定の分子内の原子のさまざまな空間配置を研究するものです。 ラジカルハロゲン化の立体化学は、次の 3 つの異なる状況から理解できます。
新しいキラル中心を形成するためのハロゲン化:
例えば、ブタンのラジカルハロゲン化により生成物 2-クロロブタンと 1-クロロブタンが形成され、前者はキラ…
ラジカルハロゲン化の立体化学は、反応する分子がキラルかアキラルかによって異なります。
例えば、アキラルn-ブタンは、ラジカル塩素化により、1-および2-クロロブタンを生成します。この反応により、生成物の1つがラセミ混合物であるため、新しいキラル中心が導入されます。
ラセミ混合物の形成は、アキラル三方晶平面ラジカル中間体の生成によって駆動され、塩素はどちらの面からでも攻撃でき、同量のRおよびSエナンチオマーを生成します。
これにより、炭素2水素は本質的にエナンチオトピアになります。
同様に、既存のキラル中心でのラジカルハロゲン化もラセミ混合物を形成します。
ここで、ラジカル中間体は反応物の構造を失い、アキラルになり、どちらの側からでもハロゲン攻撃が可能になり、同量のエナンチオマーが生成されます。
対照的に、ラジカルハロゲン化に関与しないキラルカーボンを含むキラル化合物は、ジアステレオマー生成物を与え、第2のキラル中心を導入します。
既存のキラル中心は、三方晶平面ラジカル中間をキラルにします。その結果、塩素は一方の面で他方の面よりも大きく攻撃し、不等量のキラルなジアステレオマー生成物を生成します。
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Q1: Why does radical halogenation of achiral molecules produce racemic mixtures?
Radical halogenation of achiral molecules creates a trigonal planar radical intermediate, which is achiral. The halogen can attack this intermediate from either face with equal probability, generating equal amounts of R and S enantiomers. This produces a racemic mixture even though a new chiral center is formed. The trigonal planar geometry eliminates stereochemical preference during the attack.
Q2: What happens to stereochemistry when radical halogenation occurs at an existing chiral center?
When radical halogenation occurs at an existing chiral center, the resulting radical intermediate loses the original molecule's configuration and becomes achiral. Despite the starting material being chiral, the trigonal planar intermediate allows halogen attack from either face equally, producing a 1:1 ratio of enantiomers and forming a racemic mixture.
Q3: How does radical halogenation produce diastereomers instead of enantiomers?
Diastereomers form when radical halogenation occurs at a position other than an existing chiral center. The existing chiral center makes the trigonal planar radical intermediate chiral, causing the halogen to attack one face preferentially over the other. This unequal attack produces diastereomeric products in unequal amounts, introducing a second chiral center.
Q4: What role does the trigonal planar geometry of radical intermediates play in stereochemistry?
The trigonal planar geometry of radical intermediates is crucial to stereochemical outcomes. When the intermediate is achiral, both faces are equivalent, allowing equal halogen attack and producing racemic mixtures. When the intermediate is chiral due to an existing stereocenter, the two faces become diastereotopic, leading to unequal halogen attack and diastereomeric products.
Q5: Are the hydrogens on carbon-2 of n-butane equivalent during radical chlorination?
No, the hydrogens on carbon-2 of n-butane are enantiotopic. Although they appear equivalent in the starting material, radical chlorination of either hydrogen produces different enantiomers. The trigonal planar radical intermediate allows chlorine attack from either face, generating R and S products in equal amounts as a racemic mixture.
Q6: How does the presence of a chiral center affect the facial selectivity of halogen attack?
An existing chiral center makes the trigonal planar radical intermediate chiral, differentiating the two faces. This creates diastereotopic faces, causing the halogen to attack one face preferentially. The unequal attack produces diastereomeric products in unequal amounts, unlike achiral intermediates where both faces are equivalent and attack occurs equally.
Q7: What is the difference between enantiotopic and diastereotopic hydrogens in radical halogenation?
Enantiotopic hydrogens produce enantiomers when substituted, as seen with carbon-2 hydrogens in n-butane, which form a racemic mixture. Diastereotopic hydrogens produce diastereomers when substituted, occurring when an existing chiral center influences the radical intermediate. The distinction depends on whether the resulting products are enantiomers or diastereomers.