15.13
質量 100 kg、半径 0.2 メートル、回転半径 0.15 メートルの芝生用ローラーを考えてみましょう。 このローラーには水平面から 60 度の角度で 200 N の力がかかります。 芝生用ローラーの角加速度はいくらになるでしょうか?
ローラーと地面の間の摩擦は 2 つの係数によって特徴付けられ…
質量100 kg、半径0.2メートル、回転半径0.15メートルの芝生ローラーを考えてみましょう。200 Nの力が水平に対して60度の角度で加えられる場合、芝生ローラーの角加速度はどれくらいですか?
地面と芝生ローラーの間の静摩擦係数は0.15で、動摩擦係数は0.1です。
滑らずに転がると仮定すると、瞬間速度がゼロの点Aのモーメントは、加えられた力の水平成分を使用して計算されます。
点Aでは、慣性モーメントは平行軸定理を使用して計算されます。
モーメント方程式の点Aでの慣性モーメントの値を代入すると、角加速度の値が得られます。
スリップ運動のない転がりの仮定は、芝生ローラーの中心の動きから生じる摩擦力が最大静的摩擦力よりも小さい場合に有効です。
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Q1: How do you calculate angular acceleration for a rolling object using the instantaneous center of zero velocity?
The instantaneous center of zero velocity, or point A, serves as the reference for calculating moments in rolling motion. The horizontal component of the applied force creates a moment about this point. Using the parallel axis theorem, the moment of inertia at point A is determined. Substituting this moment of inertia into the moment equation yields the angular acceleration of the rolling object.
Q2: What is the parallel axis theorem and why is it used in rolling motion problems?
The parallel axis theorem relates the moment of inertia about different axes. In rolling motion problems, it calculates the moment of inertia at the instantaneous center of zero velocity, which differs from the center of mass. This calculation is essential for applying the moment equation and determining angular acceleration when forces act on rolling objects.
Q3: When is the rolling without slipping assumption valid for a moving object?
Rolling without slipping is valid when the frictional force from the object's center motion remains lower than the maximum static frictional force. This condition ensures the object maintains contact with the surface without sliding. If the required friction exceeds the maximum static friction available, the object will slip, invalidating the rolling without slipping assumption.
Q4: How do static and kinetic friction coefficients affect rolling motion analysis?
Static friction coefficient determines the maximum frictional force available before slipping occurs, critical for validating rolling without slipping. Kinetic friction coefficient applies if slipping does occur. Both coefficients characterize the interaction between the rolling object and the surface, influencing whether the rolling without slipping assumption holds true.
Q5: What role does the radius of gyration play in calculating moment of inertia?
The radius of gyration represents the distance from the axis where the entire mass could be concentrated to produce the same moment of inertia. It simplifies moment of inertia calculations for complex shapes. Combined with mass, it allows quick determination of the moment of inertia needed for the moment equation in general plane motion problems.
Q6: How does the angle of an applied force affect the motion of a rolling object?
The angle of the applied force determines its horizontal and vertical components. Only the horizontal component contributes to the moment about the instantaneous center of zero velocity, affecting angular acceleration. The vertical component influences the normal force and thus the maximum available friction, impacting whether rolling without slipping occurs.
Q7: What steps are involved in solving a general plane motion problem with rolling constraints?
First, identify the instantaneous center of zero velocity and calculate the moment using the horizontal force component. Second, apply the parallel axis theorem to find moment of inertia at that point. Third, substitute into the moment equation to find angular acceleration. Finally, verify the rolling without slipping assumption by comparing required friction to maximum static friction.