2.10
熱力学過程とは、系を初期状態から最終状態へと導く一連の状態を経由する経路のことです。巡回過程では、系は初期状態に戻るため、1回の完全なサイクルにおける状態特性や状態関数(ΔT、Δp、ΔV、ΔU、ΔH)の変化はゼロとなります。しかし、サイクル中でも熱と仕事の移動は起こり得、サイクル中の純熱と正味仕事が…
熱力学系は、その状態変化を定義する一つ以上の性質によって状態が変化します。
異なる経路を経て同じ初期状態から最終状態へと移行するプロセスは、異なるプロセスとみなされます。
循環過程では系は初期状態に戻り、温度、圧力、体積などの状態関数は元の値に戻ります。しかし、サイクル中に交換される熱と仕事はゼロでないことがあります。
可逆的な過程では、系は常に平衡に近づき、微細な変化でも系と周囲の両方を元の状態に戻すことができます。このような過程での仕事は dwrev = -p dV で与えられ、熱 dqは温度で割るとエントロピーの変化に対応します。
等温過程は温度を一定に保ちますが、断熱過程では熱交換がないため 、q と dq はゼロに等しいです。
等容過程は体積を一定に保ち、等圧過程はプロセス全体を通じて圧力を一定に保ちます。定圧過程では、ΔH = qp がわかります。
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Q1: What happens to state properties during a cyclic thermodynamic process?
In a cyclic process, the system returns to its initial state, so state properties like temperature, pressure, and volume return to their original values. However, heat and work exchanged during the cycle can be nonzero. The net heat and net work over the complete cycle need not be zero, even though all state function changes equal zero.
Q2: How does a reversible process differ from an irreversible process?
A reversible process keeps the system infinitesimally close to equilibrium, allowing any infinitesimal change to restore both system and surroundings to original states. Work in reversible processes follows dwrev = -pdV. Irreversible processes proceed with finite changes and cannot restore the system and surroundings without external work, occurring when friction or finite compositional, pressure, or temperature changes are present.
Q3: What distinguishes an isothermal process from an adiabatic process?
An isothermal process maintains constant temperature by placing the system in a thermal bath at fixed temperature, while other properties like volume may change. An adiabatic process involves no heat exchange between system and surroundings, achieved using adiabatic walls, so q and dq equal zero. Both processes can change internal energy and work, but through different mechanisms.
Q4: Why is work zero in a constant-volume process?
In a constant-volume process, system volume remains fixed using rigid walls, so no pV work occurs. Since work is given by dwrev = -pdV, when dV equals zero, the work term becomes zero regardless of pressure changes. This contrasts with constant-pressure processes, where volume can change and work is performed on or by the system.
Q5: How is enthalpy related to heat in a constant-pressure process?
In a constant-pressure process, the heat absorbed or released equals the change in enthalpy: ΔH = qp. This relationship makes enthalpy particularly useful for analyzing chemical reactions and physical changes occurring at constant pressure, such as processes in open containers at atmospheric pressure.
Q6: What defines different thermodynamic process types?
Common process types are defined by what remains constant: isothermal processes hold temperature T constant, adiabatic processes maintain zero heat transfer (q = 0), isochoric processes keep volume V constant with zero work, and isobaric processes maintain constant pressure p. Each constraint determines how the system's energy and work are distributed during state changes.
Q7: How do different paths affect the relationship between initial and final states?
Processes connecting the same initial and final states via different paths are considered different processes. Although state functions like temperature, pressure, and volume depend only on initial and final states, the heat and work exchanged differ for each path. This distinction is central to understanding state functions and exact differentials in thermodynamics.