6.3
多変数の線形方程式系は、複数の未知数や制約条件を含む複雑な状況をモデル化する上で極めて重要です。このような方程式系は、複数の条件を同時に満たす必要がある関係を表すために、さまざまな分野で広く活用されています。系内の各変数は未知の量に対応し、各方程式は線形の制約を課すことで、現実世界の問題を体系的に分…
ガウス消去法は、一方の方程式を使用して他方の方程式から変数を除去することにより、n個の変数のm個の線形方程式系を解きます。
冷蔵庫、食器洗い機、ストーブを製造する工場 A、B、C を考えてみましょう。
工場出荷時の稼働日数を変数として、線形方程式 E1、E2、および E3 を使用してシステムをモデル化できます。このシステムは、ガウス消去法を使用して解かれます。
まず、変数を 1 つ削除します。X を選択します。E1 に 2 を掛けます。次に、E2 から減算して解きます。次に、E2 を結果に置き換えてx項を排除し、E4を形成します。
E3 から x 項を削除するには、E1 に 5 を掛け、E3 に 4 を掛けてから、4E3 から 5E1 を減算して、x 項なしで E5 を形成します。
ここで、E5からy項を削除するには、E4 に11を掛け、E5 に4を掛けてから、zを解きます。
z を E4 に逆代入することにより、y が得られます。
同様に、y と z を E1 に逆代入して x を見つけます。
このソリューションでは、ファクトリ A が 6 日間、B が 2 日間、C が 3 日間稼働していることを示しています。
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Q1: What is Gaussian elimination and how does it solve systems of equations?
Gaussian elimination solves systems of linear equations by using one equation to eliminate a variable from the others. The method simplifies the system into an upper triangular form through elementary row operations like multiplying and subtracting equations. Once in triangular form, back-substitution determines variable values starting from the bottom equation and working upward to find the complete solution.
Q2: How do you eliminate variables in the first step of Gaussian elimination?
To eliminate a variable, choose which variable to remove first. Multiply one equation by a constant, then subtract it from another equation containing that variable. This creates a new equation without the chosen variable. Repeat this process for each variable across all equations to progressively build the triangular form.
Q3: What is back-substitution and when is it used?
Back-substitution is used after the system is converted to upper triangular form. Starting with the bottom equation, solve for the last variable. Substitute that value into the equation above it to find the next variable. Continue this process upward through all equations until all variable values are determined.
Q4: How many solutions can a system of three linear equations have?
A system of three equations can have three solution types: a unique solution when the three planes intersect at a single point; infinitely many solutions when planes intersect along a line or overlap entirely; or no solution when planes are parallel or do not intersect at a common point. The geometric configuration determines which outcome occurs.
Q5: What are elementary row operations in Gaussian elimination?
Elementary row operations are manipulations used to simplify a system without changing its solution. These include swapping rows to place non-zero coefficients in leading positions, scaling rows by multiplying by constants, and eliminating variables by subtracting linear combinations of rows. These operations transform the system into upper triangular form.
Q6: How can Gaussian elimination be applied to real-world problems?
Gaussian elimination models complex scenarios with multiple unknowns and constraints. For example, factory production problems use variables for run days and equations for output constraints. By solving the resulting system, you find how many days each factory must operate to meet production goals, demonstrating how linear equations represent real resource allocation and planning decisions.
Q7: Why is upper triangular form important in solving systems?
Upper triangular form simplifies solving because each equation contains progressively fewer variables. The bottom equation has only one variable, making it solvable directly. Each equation above contains one additional variable, allowing systematic back-substitution. This structured arrangement makes finding all variable values efficient and organized.