20.18
입체화학은 주어진 분자에서 원자의 다양한 공간 배열에 대한 연구입니다. 라디칼 할로겐화의 입체화학은 세 가지 상황에서 이해할 수 있습니다.
새로운 키랄 중심을 형성하기 위한 할로겐화:
예를 들어, 부탄의 라디칼 할로겐화는 2-클로로부탄과 1-클로로부탄 생성물을 형성하는…
라디칼 할로겐화의 입체화학은 반응하는 분자가 키랄인지 아키랄인지에 따라 달라집니다.
예를 들어, 아키랄 n-부탄은 라디칼 염소화 시 1-클로로부탄과 2-클로로부탄을 제공합니다. 이 반응은 새로운 키랄 중심을 도입하는데, 산물 중 하나가 라세미 혼합물이기 때문입니다.
라세미 혼합물의 형성은 아키랄 삼각 평면 라디칼 중간체의 생성에 의해 주도되며, 염소는 양쪽 면에서 공격할 수 있어 동일한 양의 R 및 S 거울상 이성질체를 생성할 수 있습니다.
이것은 탄소-2 수소를 자연에서 거울상 이성질화로 만듭니다.
유사하게, 기존 키랄 중심에서의 라디칼 할로겐화도 라세미 혼합물을 형성합니다.
여기서 라디칼 중간체는 반응물의 구성을 잃고 아키랄이 되어 양쪽에서 할로겐 공격을 가능하게 하고 동일한 양의 거울상 이성질체를 생성합니다.
대조적으로, 라디칼 할로겐화에 관여하지 않는 키랄 탄소를 가진 키랄 화합물은 부분입체이성질체 생성물을 제공하여 두 번째 키랄 중심을 도입합니다.
기존 카이랄 중심은 삼각 평면 라디칼 중간 키랄을 만듭니다. 결과적으로, 염소는 한쪽 면이 다른 면보다 더 많이 공격하고 불균등한 양의 키랄, 부분입체이성체 생성물을 생성합니다.
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Q1: Why does radical halogenation of achiral molecules produce racemic mixtures?
Radical halogenation of achiral molecules creates a trigonal planar radical intermediate, which is achiral. The halogen can attack this intermediate from either face with equal probability, generating equal amounts of R and S enantiomers. This produces a racemic mixture even though a new chiral center is formed. The trigonal planar geometry eliminates stereochemical preference during the attack.
Q2: What happens to stereochemistry when radical halogenation occurs at an existing chiral center?
When radical halogenation occurs at an existing chiral center, the resulting radical intermediate loses the original molecule's configuration and becomes achiral. Despite the starting material being chiral, the trigonal planar intermediate allows halogen attack from either face equally, producing a 1:1 ratio of enantiomers and forming a racemic mixture.
Q3: How does radical halogenation produce diastereomers instead of enantiomers?
Diastereomers form when radical halogenation occurs at a position other than an existing chiral center. The existing chiral center makes the trigonal planar radical intermediate chiral, causing the halogen to attack one face preferentially over the other. This unequal attack produces diastereomeric products in unequal amounts, introducing a second chiral center.
Q4: What role does the trigonal planar geometry of radical intermediates play in stereochemistry?
The trigonal planar geometry of radical intermediates is crucial to stereochemical outcomes. When the intermediate is achiral, both faces are equivalent, allowing equal halogen attack and producing racemic mixtures. When the intermediate is chiral due to an existing stereocenter, the two faces become diastereotopic, leading to unequal halogen attack and diastereomeric products.
Q5: Are the hydrogens on carbon-2 of n-butane equivalent during radical chlorination?
No, the hydrogens on carbon-2 of n-butane are enantiotopic. Although they appear equivalent in the starting material, radical chlorination of either hydrogen produces different enantiomers. The trigonal planar radical intermediate allows chlorine attack from either face, generating R and S products in equal amounts as a racemic mixture.
Q6: How does the presence of a chiral center affect the facial selectivity of halogen attack?
An existing chiral center makes the trigonal planar radical intermediate chiral, differentiating the two faces. This creates diastereotopic faces, causing the halogen to attack one face preferentially. The unequal attack produces diastereomeric products in unequal amounts, unlike achiral intermediates where both faces are equivalent and attack occurs equally.
Q7: What is the difference between enantiotopic and diastereotopic hydrogens in radical halogenation?
Enantiotopic hydrogens produce enantiomers when substituted, as seen with carbon-2 hydrogens in n-butane, which form a racemic mixture. Diastereotopic hydrogens produce diastereomers when substituted, occurring when an existing chiral center influences the radical intermediate. The distinction depends on whether the resulting products are enantiomers or diastereomers.