29.1
직렬 저항-인덕터(R-L) 회로에서 시간 주기의 시작 부분에서 스위치를 닫으면 3상 단락 회로, 즉 무부하 동기기의 3상이 모두 단락되는 고장 상태가 시뮬레이션됩니다. 고장 임피던스가 없고 초기 전류가 없는 경우 초기 전압은 소스 전압의 위상각에 따라 결정됩니다.
키르…
직렬 RL 회로를 고려하십시오.
스위치가 0과 같은 시간에 닫히면 무부하 동기 기계에서 3상 단락을 모방합니다.
제로 고장 임피던스 또는 볼트 고장이 주어지고 초기 전류가 0인 경우 소스 각도는 초기 소스 전압을 결정합니다.
이 회로의 KVL 방정식은 총 비대칭 고장 전류와 두 가지 구성 요소를 산출합니다.
대칭 또는 정상 상태 고장 전류라고도하는 AC 고장 전류는 정현파입니다.
DC 오프셋 전류는 인덕턴스 대 저항 비율로 시간 상수로 기하급수적으로 감소합니다.
그 크기는 소스 각도에 따라 달라지며, 소스 각도가 2에 걸쳐 세타에 파이를 더한 값과 같을 때 최고조에 이릅니다.
가장 큰 고장 전류는 특정 소스 각도에서 발생합니다.
그런 다음 최대 dc 오프셋을 갖는 rms 비대칭 고장 전류를 계산하고 사이클 및 주파수 측면에서 시간 상수와 시간을 대체하여 단순화합니다.
이 전류는 rms AC 고장 전류에 비대칭 계수를 곱한 값과 같으며 rms 전류는 tau가 증가함에 따라 감소합니다.
저항 비율에 대한 리액턴스가 높을수록 더 높은 rms 전류 값이 생성됩니다.
View the full transcript and gain access to JoVE Core videos
Q1: What are the two main components of asymmetrical fault current in an R-L circuit?
Asymmetrical fault current consists of two components: the AC fault current (also called symmetrical or steady-state fault current), which follows a sinusoidal pattern, and the DC offset current, which decays exponentially over time. The DC offset's magnitude depends on the source angle and peaks at a specific phase angle. Together, these components determine the total fault current response when a switch closes in a series R-L circuit.
Q2: How does the DC offset current decay in a series R-L circuit?
The DC offset current decays exponentially with a time constant defined by the inductance-to-resistance ratio (L/R). The rate of decay depends directly on this ratio; higher inductance relative to resistance results in slower decay. The magnitude of the DC offset varies with the source angle, peaking when the source angle equals theta plus pi over two, which determines the maximum initial offset current.
Q3: What does a series R-L circuit model when the switch closes at time zero?
When the switch closes at time zero in a series R-L circuit with zero fault impedance and zero initial current, it simulates a three phase short circuit in an unloaded synchronous machine. The source voltage phase angle determines the initial voltage at the moment of switching. This setup allows engineers to analyze fault conditions and understand how circuit parameters affect the resulting fault current behavior.
Q4: How is the RMS asymmetrical fault current calculated?
The RMS asymmetrical fault current is calculated by multiplying the RMS AC fault current by an asymmetry factor that reflects the influence of the DC offset current. The calculation expresses the time constant and time in terms of cycles and frequency. As the time constant increases, the RMS current decreases, demonstrating that higher inductance-to-resistance ratios yield higher RMS current values.
Q5: What role does Kirchhoff's Voltage Law play in fault current analysis?
Kirchhoff's Voltage Law (KVL) is applied to the series R-L circuit to determine the total asymmetrical fault current and its two components. By analyzing the voltage equation across the resistor and inductor, engineers can derive expressions for both the AC and DC offset currents. This fundamental circuit analysis technique enables prediction of fault current magnitude and behavior under different source angle conditions.
Q6: Why does the maximum fault current occur at a specific source angle?
The magnitude of the DC offset current, which significantly contributes to the total asymmetrical fault current, varies with the source angle. The DC offset peaks when the source angle equals theta plus pi over two, resulting in the largest total fault current at this specific phase angle. Understanding this relationship helps engineers predict worst-case fault scenarios and design protective systems accordingly.
Q7: How does the reactance-to-resistance ratio affect RMS fault current?
Higher reactance-to-resistance ratios result in higher RMS asymmetrical fault current values. This ratio directly influences the time constant (L/R), which governs the decay rate of the DC offset component. Since the asymmetry factor depends on this time constant, circuits with greater inductance relative to resistance produce larger and more persistent fault currents, requiring more robust protective equipment.