Name: using parts and substitution for area
Uploaded: 2026-01-12T12:24:42.000Z
Duration: 1 min 23 s
Channel: JoVE

Definite integrals of products of two functions over fixed intervals can be solved using integration by parts.To solve the right-hand side of this expression, the difference of the product of functions will be evaluated between the interval&#8217;s endpoints, and the remaining term will be treated as a definite integral.A useful example is the integral of the inverse tangent function. Because no standard integral formula exists for this function, the integrand is instead treated as a product of the inverse tangent and the constant 1.The inverse tangent is taken as the function to be differentiated, and the constant is integrated.Substituting into the integration by parts formula, the first term can be solved by directly evaluating the product at the endpoints. The remaining integral can then be solved by substitution.A new variable, t, is set equal to 1 plus x squared and the limits of integration are adjusted. The integral then becomes a reciprocal expression that simplifies to a logarithmic form.The natural log of one equals zero, so the final expression simplifies to show the area under the curve between the two limits.

integration by parts: definite integrals

Definite integrals involving the product of two functions over a fixed interval can be evaluated using integration by parts. This method rewrites the integral as the difference of a product evaluated at the endpoints and a remaining definite integral that is often simpler to compute.A representative example is the definite integral of the inverse tangent function. Since there is no direct integration formula for arctan &#8289;x, the integrand is rewritten as a product of arctan&#8289; x and the constant function 1. The inverse tangent is chosen for differentiation, while the constant is integrated, simplifying the structure of the problem.Substituting these choices into the integration by parts formula allows the first term to be evaluated directly by computing the product at the interval&#8217;s endpoints. The remaining term is a definite integral that can be solved using substitution. By letting a new variable equal 1+x2, the integral is transformed into a reciprocal form that integrates to a logarithmic expression, with the limits adjusted accordingly.Evaluating the logarithmic term at the bounds simplifies the result, since the natural logarithm of one is zero. The final expression represents the area under the inverse tangent curve between the given limits, illustrating how integration by parts can be applied effectively to definite integrals involving functions without elementary antiderivatives.

Integration by Parts: Definite Integrals

Definite integrals involving the product of two functions over a fixed interval can be evaluated using integration by parts. This method rewrites the ...

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Calculus

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Techniques of Integration

KEY TERMS AND CONCEPTS

using parts and substitution for area

Integration by parts can make a definite integral easier to solve when the integrand is a product over a fixed interval. The method rewrites the problem as a product at the endpoints minus another definite integral that may be simpler to evaluate.

A useful example is the definite integral of inverse tangent, or arctan x. Since there is no direct integration formula for arctan x, the integrand is written as arctan x times the constant function 1. The inverse tangent is chosen to differentiate, while the constant is chosen to integrate, which simplifies the setup.

After the integration by parts formula is applied, the first term is found by evaluating the product at the interval endpoints. The remaining definite integral is then handled with substitution. Letting the new variable equal 1 + x2 changes the integral into a reciprocal form, which integrates to a logarithmic expression.

The limits must be adjusted to match the new variable. When the logarithmic term is evaluated at the bounds, the natural logarithm of one becomes zero. The final result gives the area under the inverse tangent curve between the given limits and shows how integration by parts can work well for definite integrals without elementary antiderivatives.

Using Parts and Substitution for Area

integration by parts: indefinite integrals

integration-by-parts-indefinite-integrals

Integration by Parts in AC Circuit Analysis

Integration by parts is a calculus method for handling integrals that contain a product of two functions. It is useful when direct integration is not practical. The method comes from the product rule for differentiation, which says that the derivative of a product is the derivative of the first function times the second, plus the first function times the derivative of the second. By integrating that product-rule identity and rearranging the terms, the integration by parts formula is obtained.

Integration by parts can make a definite integral easier to solve when the integrand is a product over a fixed interval. The method rewrites the problem as a product at the endpoints minus another definite integral that may be simpler to evaluate. A useful example is the definite integral of inverse tangent, or arctan x. Since there is no direct integration formula for arctan x, the integrand is written as arctan x times the constant function 1. The inverse tangent is chosen to differentiate,...

integration by parts: problem solving

Integration by Parts for Signal Processing

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integrals of powers of sine and cosine

Solving Trig Integrals with Odd and Even Powers

Trigonometric integrals are solved by looking at the powers of sine and cosine in the expression. These integrals appear often in calculus, and they can also be useful in physics and engineering. For integrals of the form sin^m(x)cos^n(x), the first step is to check whether the sine power or the cosine power is odd. If the sine power is odd, one sine factor is separated from the integrand. That leaves an even power of sine. The remaining sine terms are rewritten using the Pythagorean identity,...

integrals of powers of secant and tangent

integrals-of-powers-of-secant-and-tangent

Solving Secant and Tangent Integrals

Integrals of secant and tangent powers are often solved by choosing a trig substitution that matches the integrand. The key idea is to use the parity of the exponents, which means whether a power is even or odd. A good substitution lets part of the integrand pair with the derivative of a trig function. When the power of secant is even, tangent is the better substitution variable. Since the derivative of tangent is secant squared, a factor of sec^2 x can be split off. The remaining even power...

trigonometric substitution

Finding Ellipse Area with Trig Substitution

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integration of rational functions using partial fractions

integration-of-rational-functions-using-partial-fractions

Splitting Rational Integrals Into Simpler Parts

Rational functions are ratios of two polynomials, and their integrals can be simplified by breaking them into smaller parts. A rational function is proper when the degree of the numerator is less than the degree of the denominator. When that is true, partial fraction decomposition rewrites the expression as a sum of simpler rational terms. To decompose a proper rational function, unknown constants are placed into the simpler terms. The denominator is then multiplied through to remove the...

rationalizing substitutions

Integrating Radicals with Rational Substitution

Integrating radicals can be easier when a rationalizing substitution turns the expression into a rational form. This method is useful when standard techniques do not work well because the integrand contains a radical, such as a cube root. The transcript uses a rod as a real-world example. Its linear mass density depends on a constant linear density, a characteristic length, and the distance from the left end of the rod. Finding the total mass means integrating that density over the length of...

approximate integration

Riemann Sum Area Estimates

Riemann sums estimate the area under a curve when an exact definite integral is hard to find. This often happens when a function has no known antiderivative or cannot be written in a closed form. It also happens when the function comes from measured data instead of a formula. The method works by splitting the interval of integration into equal parts. Each subinterval gets a rectangle, and the rectangle height comes from the function value at one chosen point in that part. Adding the rectangle...

trapezoidal rule

Estimating Distance from Velocity Data

Estimating distance from velocity data is a common use of the trapezoidal rule. In physics and engineering, velocity is often recorded at separate time points instead of as one continuous equation. Numerical integration gives a way to approximate the total displacement from those measurements. The method divides the full time interval into equal parts. For each part, the velocities at the two endpoints are joined with a straight line on a velocity-time graph. That line creates a trapezoid.

simpson's rule i

Estimating Area with Simpson’s Rule

Simpson’s Rule is a numerical integration method for estimating the value of a definite integral. It is useful when an exact antiderivative is hard or impossible to find. The method works by fitting a unique parabola through three equally spaced points on a curve and then integrating that quadratic over the interval. This approach can give a very accurate area estimate from only a few sampled values. It works well for many smoothly varying functions. That makes it a practical tool when a curve...

simpson's rule ii

Simpson's Rule for Curved Sheet Area

Simpson's Rule helps estimate the area under a smooth curve, such as the curved profile of metal roofing sheets. In warehouse roofing, corrugated or curved sheets are used because they add strength, improve water drainage, and support better ventilation. To plan materials and design more accurately, engineers often need the area of these curved surfaces. The sheet shape can often be treated like a parabolic curve because it changes smoothly along its length. That makes numerical integration a...

improper integrals: infinite intervals

Improper Integrals and Exponential Decay

Improper integrals with infinite intervals appear when one limit of integration goes to positive or negative infinity. In that case, the area under the curve is unbounded, so ordinary definite integral methods do not apply directly. The integral is then defined by a limit, which helps show whether the total area is finite even when the interval is infinite. This idea is useful in exponential decay models. One example is the total integrated intensity of light moving through a uniform medium,...

improper integrals: discontinuous integrands

improper-integrals-discontinuous-integrands

Improper Integrals at an Endpoint

Improper integrals can appear when a definite integral has a discontinuity at one endpoint. The integrand may be undefined or become infinite there. In that case, the area under the curve is unbounded near the boundary. This behavior is often linked to a vertical asymptote at the edge of the interval. To evaluate this kind of integral, the endpoint is replaced with a variable. The integral is then written over an interval where the function is defined. After that, a limit is taken as the...

key terms and concepts

Learn how integration by parts and substitution simplify a definite integral of arctan x. The method turns the problem into endpoint values and a logarithm.

Using Parts and Substitution for Area | JoVE K12

The JoVE Core Calculus collection provides a comprehensive visual guide to the entire calculus sequence, seamlessly connecting mathematical theory to real-world applications in physics and economics. Through dynamic animated lessons, the course transitions smoothly from foundational single-variable concepts to advanced multivariable topics. Students will explore everything from standard differentiation and integration to spatial vectors, multi-dimensional derivatives, and complex vector fields. By breaking down abstract coordinate systems, infinite series, and spatial motion, this structured approach builds the robust analytical skills and advanced mastery essential for STEM success.

calculus

Using Parts and Substitution for Area

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