6.2
An airplane trip between two countries presents a classic puzzle for solving a system of equations.
The distance is 1260 kilometers. Flying against the wind takes 3 hours, while flying with the wind takes only 2 hours.
Although both trips cover the same distance, the time differs due to the wind’s speed, which remains constant throughout the journey.
Let x be the airplane’s speed in still air, and y be the wind’s speed.
Since distance equals speed multiplied by time, the effective speed against the wind is the airplane’s speed minus the wind’s speed. Multiplying this by 3 hours gives 1260 kilometers.
For the journey with the wind, the effective speed is the airplane’s speed plus the wind’s speed. Multiplying this by 2 hours also gives 1260 kilometers.
These two relationships form a pair of linear equations. Using the elimination method, adding the two equations removes the wind’s speed, leaving a simpler equation in x.
This reveals the airplane’s true speed.
Substituting this value into either equation gives the wind’s speed.
Solving a system of linear equations is a fundamental concept in algebra. A system of equations consists of two or more linear equations involving the…
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