Redox, which is shorthand for reduction-oxidation, is a type of chemical reaction classified by the net transfer of electrons. In this reaction, one molecule loses electrons, called oxidation, and the other molecule gains electrons, called reduction.
To help you differentiate between the two, remember the phrase 'OIL-RIG', which stands for 'oxidation is losing, reduction is gaining'. The molecule that is oxidized is called the reducing agent because it reduces the other reactant. Similarly, the molecule that is reduced is called the oxidizing agent because it oxidizes the other molecule.
Now that we have the terminology sorted out, let's look at an example of a redox reaction, the formation of the mineral magnesium oxide. During the reaction, each magnesium atom loses two electrons. Thus, magnesium is oxidized. Each oxygen atom gains two electrons; thus, oxygen is reduced.
However, not all reactions are redox reactions. For example, the reaction of calcium oxide with carbon dioxide to form calcium carbonate is not a redox reaction. So, how can we identify a redox reaction?
To do this, we track the oxidation number of each element as it goes from reactant to product. The oxidation number is the hypothetical charge that an atom would have if its bonds to different elements were ionic, meaning that the electrons are assigned to the more electronegative atom. The sum of the oxidation numbers in a molecule equals its overall charge.
Let's look back at magnesium oxide. It is a neutral compound, so the sum of the oxidation numbers for magnesium and oxygen equals zero. Magnesium can give two electrons, so its oxidation number is plus two. Oxygen can accept two electrons, so its oxidation number is minus two.
How about the reaction? Pure neutral elemental compounds have an oxidation number of zero. Thus, both magnesium and oxygen start with oxidation numbers of zero. Both magnesium and oxygen's oxidation numbers changed during the reaction, so this is a redox reaction.
Now, let's look at the calcium carbonate reaction we saw earlier. Both reactants are neutral, so the sum of the oxidation numbers for both compounds is zero. As we saw with magnesium oxide, calcium has an oxidation number of plus two and oxygen minus two. Then, the carbon in the carbon dioxide molecule has an oxidation number of plus four and each oxygen minus two.
How about the product? Calcium is plus two and carbon plus four, just like in the reactants. Each oxygen is minus two, totaling minus six, with the net oxidation number zero. Since none of the oxidation numbers have changed, this is not a redox reaction.
Now let's introduce the four types of redox reactions. The first is a single displacement reaction, where one atom displaces another. You'll see this in a thermite reaction, where one metal is reduced, and the other metal is oxidized.
The next type is a combustion reaction, which occurs between a fuel and oxidant to form oxidized products and heat. You see this in the lab during the combustion of methane with oxygen when using a Bunsen burner.
The third is a synthesis reaction, where two reactants combine to form one product, like in the synthesis of ammonia, where nitrogen is combined with hydrogen to form ammonia.
Finally, the fourth type is a decomposition reaction, where a reactant absorbs enough energy to break its bonds to form smaller compounds. This is what happens with fireworks, where potassium chlorate decomposes to potassium chloride and oxygen after heating.
In this lab, you'll perform and identify various types of redox reactions that transform solid copper to copper oxide, and then back again to solid copper.
Source: Smaa Koraym at Johns Hopkins University, MD, USA
In the first half of this lab, you will make solid copper. In this reaction, the solid copper is first oxidized by the strong oxidizing agent, nitric acid, to form water and the salt copper nitrate. The copper nitrate quickly dissociates into the ions, copper(2+) and nitrate, in water. The nitrate anions are reduced to NO2 gas, which is confirmed by the presence of reddish-brown fumes. The presence of copper ions is indicated by a greenish-blue tint. Adding a base to the mixture changes the color to blue as the copper(II) hydroxide precipitate is formed. The copper(II) hydroxide is relatively unstable; thus, when heat is introduced, a decomposition reaction occurs. In this reaction, water is removed to produce copper oxide, which appears as a black precipitate.
| MassCu initial (g) | |
| MassCu final (g) | |
| Percent yield |
The copper oxide produced in the previous lab section is insoluble in water but can be dissolved in sulfuric acid. When this occurs, the copper(2+) cations and the sulfate anions are reintroduced through a double displacement reaction. When zinc is added in the final step, the copper(2+) ions are reduced to solid copper through a single displacement reaction.
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Q1: What happens when copper reacts with nitric acid in this lab?
Solid copper is oxidized by nitric acid to form copper nitrate, water, and NO2 gas. The copper nitrate dissociates into copper(2+) ions and nitrate anions in water. The reddish-brown fumes confirm NO2 gas production, while a greenish-blue tint indicates the presence of copper ions in solution.
Q2: How is copper oxide formed from copper(II) hydroxide?
Copper(II) hydroxide precipitate forms when a base is added to the copper solution, creating a blue color. When heated to 85°C, the copper(II) hydroxide undergoes decomposition, removing water and producing black copper oxide precipitate. This thermal decomposition converts the unstable hydroxide into the more stable oxide form.
Q3: What role does zinc play in recovering solid copper from copper oxide?
Zinc acts as a reducing agent in a single displacement reaction with copper sulfate solution. When zinc is added, copper(2+) ions are reduced to solid copper while zinc is oxidized to zinc(2+) ions. The solution becomes colorless once all copper ions are reduced, indicating complete copper recovery.
Q4: Why is hydrochloric acid added after the zinc displacement reaction?
Hydrochloric acid dissolves excess zinc remaining in the solid copper precipitate through a neutralization reaction that produces bubbling. Adding acid in increments ensures complete removal of unreacted zinc without over-dissolving the copper product, leaving pure copper for final collection and weighing.
Q5: How do you determine if the final copper product is pure?
Test for methanol using an indicating desiccant that changes from blue to turquoise if present. Drop 6 M HCl on the product; bubbling indicates residual NaOH contamination. Pure copper appears as dark-red granules. Black color suggests incomplete conversion and the presence of copper oxide instead.
Q6: What does percent yield calculation reveal about the copper recovery experiment?
Percent yield is calculated by dividing the final copper mass by the initial copper mass and multiplying by 100. Yields exceeding 100% indicate calculation errors or residual moisture on the product. This metric shows how efficiently copper was recovered through the oxidation and reduction sequence.
Q7: Why is methanol used in the final drying step instead of water?
Methanol is used because it evaporates more readily than water at room temperature, ensuring thorough drying of the copper precipitate without heat damage. Multiple methanol washes followed by extended vacuum application remove residual moisture and impurities, preparing the copper for accurate final mass measurement.
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