Question 1

What are the products formed when an ester is reduced with lithium aluminum hydride?

Accepted Answer

Lithium aluminum hydride reduces esters to two primary alcohols: one derived from the acyl group and another from the alkoxy group. This occurs because the reaction proceeds through nucleophilic acyl substitution, where the hydride ion attacks the carbonyl carbon, forming an aldehyde intermediate that undergoes further reduction to yield the final alcohol products.

Question 2

Why does ester reduction with lithium aluminum hydride require two equivalents of the reducing agent?

Accepted Answer

Two equivalents are needed because the reaction occurs in two stages. The first hydride ion reduces the ester to an aldehyde intermediate, and the second hydride ion attacks the aldehyde carbonyl to form an alkoxide, which is then protonated to yield the primary alcohol product.

Question 3

What is the role of the tetrahedral intermediate in ester reduction?

Accepted Answer

The tetrahedral intermediate forms when the hydride ion nucleophilically attacks the carbonyl carbon of the ester. This intermediate is unstable and quickly collapses, allowing the alkoxide ion to depart as a leaving group. This collapse regenerates the carbonyl group, forming the aldehyde that proceeds to the next reduction step.

Question 4

How can you selectively reduce an ester to an aldehyde instead of a primary alcohol?

Accepted Answer

Use a milder reducing agent like lithium tri(tert-butoxy) aluminum hydride or diisobutylaluminum hydride at low temperature, approximately −78 °C. These conditions prevent the second reduction step, allowing the reaction to stop at the aldehyde intermediate rather than proceeding to the primary alcohol.

Question 5

What functional groups are produced at each stage of the ester reduction mechanism?

Accepted Answer

The mechanism produces three key intermediates: first, a tetrahedral intermediate forms after hydride attack; second, an aldehyde intermediate results from carbonyl reformation and alkoxide departure; finally, an alkoxide intermediate forms after the second hydride attack, which is protonated to yield the primary alcohol product.

Question 6

How does lithium aluminum hydride function as a reducing agent in ester reduction?

Accepted Answer

Lithium aluminum hydride acts as a source of hydride ions that function as nucleophiles. These hydride ions attack the electrophilic carbonyl carbon of the ester, initiating the reduction mechanism. The strong reducing power of lithium aluminum hydride enables complete reduction through both the aldehyde intermediate to the final primary alcohol.

Question 7

What is the significance of temperature control in selective ester reduction?

Accepted Answer

Temperature control is critical for selectivity. Low temperatures around −78 °C with milder reducing agents slow the reaction, allowing it to stop at the aldehyde intermediate. Without temperature control, the aldehyde continues to react with available hydride, proceeding to the primary alcohol, making temperature essential for achieving the desired product.

От эфиров к спиртам: восстановление гидридов