3.8
Второе кинематическое уравнение выражает конечное положение объекта через его начальное положение, пройденное расстояние с начальной постоянной скорос…
Первое кинематическое уравнение выражает скорость как функцию начальной скорости и изменения скорости.
Для вывода второго кинематического уравнения используются два уравнения для средней скорости x в интервале от t, равного нулю, до более позднего времени t. Первое уравнение для средней скорости x — это изменение смещения с течением времени, как обсуждалось в предыдущих уроках. Здесь начальная позиция обозначается как x0 в момент времени t, равный нулю, и x в более поздний момент времени t.
Предполагая, что ускорение постоянно, средняя скорость x также может быть представлена как среднее значение скоростей в начальный и конечный моменты времени. Подставляя сюда первое кинематическое уравнение, получаем уравнение для положения x как функции времени.
Это уравнение показывает, что положение объекта в любой момент времени t является суммой его начального положения, расстояния, пройденного при постоянной начальной скорости, и расстояния, пройденного при изменении скорости.
View the full transcript and gain access to JoVE Core videos
Q1: What does the second kinematic equation describe?
The second kinematic equation expresses an object's final position as the sum of its initial position, the distance moved under constant initial velocity, and the distance traveled due to acceleration. This equation applies only when acceleration remains constant throughout the motion, allowing you to calculate position at any time t.
Q2: How is the second kinematic equation derived?
The derivation uses two expressions for average velocity over a time interval. The first defines average velocity as change in displacement over change in time. The second represents average velocity as the mean of initial and final velocities. Substituting the first kinematic equation into this relationship yields the position equation.
Q3: What are the components of position in the second kinematic equation?
Position consists of three components: the initial position x0, the distance traveled at constant initial velocity, and the distance covered during the velocity change caused by acceleration. Together, these components determine where an object is located at any given time t during constant acceleration motion.
Q4: How do you solve for time using the second kinematic equation?
Rearranging the second kinematic equation produces a quadratic equation in time. Using the quadratic formula yields two mathematical solutions. However, only the positive solution is physically meaningful, since negative time would indicate an event occurring before motion began, making it unreasonable to accept.
Q5: Can you apply the second kinematic equation to a freeway merge scenario?
Yes. For a car merging onto a 200 m ramp with initial velocity 10 m/s and acceleration 2 m/s², substitute these known values into the second kinematic equation. Solving the resulting quadratic equation gives t = 10 s as the valid solution, meaning the car takes 10 seconds to travel the ramp.
Q6: Why is constant acceleration required for the second kinematic equation?
The second kinematic equation is derived assuming constant acceleration, which allows average velocity to be expressed as the mean of initial and final velocities. If acceleration varies, this relationship breaks down, and the equation no longer accurately predicts position, making constant acceleration a fundamental requirement.
Q7: How does the second kinematic equation relate to other kinematic concepts?
The second kinematic equation builds on the first kinematic equation, which relates velocity to acceleration. Together with concepts like average velocity and instantaneous velocity, these equations form a complete framework for analyzing motion with constant acceleration and solving kinematic equations problem solving scenarios.