Source: Smaa Koraym at Johns Hopkins University, MD, USA
In the first half of this lab, you will make solid copper. In this reaction, the solid copper is first oxidized by the strong oxidizing agent, nitric acid, to form water and the salt copper nitrate. The copper nitrate quickly dissociates into the ions, copper(2+) and nitrate, in water. The nitrate anions are reduced to NO2 gas, which is confirmed by the presence of reddish-brown fumes. The presence of copper ions is indicated by a greenish-blue tint. Adding a base to the mixture changes the color to blue as the copper(II) hydroxide precipitate is formed. The copper(II) hydroxide is relatively unstable; thus, when heat is introduced, a decomposition reaction occurs. In this reaction, water is removed to produce copper oxide, which appears as a black precipitate.
| MassCu initial (g) | |
| MassCu final (g) | |
| Percent yield |
The copper oxide produced in the previous lab section is insoluble in water but can be dissolved in sulfuric acid. When this occurs, the copper(2+) cations and the sulfate anions are reintroduced through a double displacement reaction. When zinc is added in the final step, the copper(2+) ions are reduced to solid copper through a single displacement reaction.
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Q1: What happens when copper reacts with nitric acid in this lab?
Solid copper is oxidized by nitric acid to form copper nitrate, water, and NO2 gas. The copper nitrate dissociates into copper(2+) ions and nitrate anions in water. The reddish-brown fumes confirm NO2 gas production, while a greenish-blue tint indicates the presence of copper ions in solution.
Q2: How is copper oxide formed from copper(II) hydroxide?
Copper(II) hydroxide precipitate forms when a base is added to the copper solution, creating a blue color. When heated to 85°C, the copper(II) hydroxide undergoes decomposition, removing water and producing black copper oxide precipitate. This thermal decomposition converts the unstable hydroxide into the more stable oxide form.
Q3: What role does zinc play in recovering solid copper from copper oxide?
Zinc acts as a reducing agent in a single displacement reaction with copper sulfate solution. When zinc is added, copper(2+) ions are reduced to solid copper while zinc is oxidized to zinc(2+) ions. The solution becomes colorless once all copper ions are reduced, indicating complete copper recovery.
Q4: Why is hydrochloric acid added after the zinc displacement reaction?
Hydrochloric acid dissolves excess zinc remaining in the solid copper precipitate through a neutralization reaction that produces bubbling. Adding acid in increments ensures complete removal of unreacted zinc without over-dissolving the copper product, leaving pure copper for final collection and weighing.
Q5: How do you determine if the final copper product is pure?
Test for methanol using an indicating desiccant that changes from blue to turquoise if present. Drop 6 M HCl on the product; bubbling indicates residual NaOH contamination. Pure copper appears as dark-red granules. Black color suggests incomplete conversion and the presence of copper oxide instead.
Q6: What does percent yield calculation reveal about the copper recovery experiment?
Percent yield is calculated by dividing the final copper mass by the initial copper mass and multiplying by 100. Yields exceeding 100% indicate calculation errors or residual moisture on the product. This metric shows how efficiently copper was recovered through the oxidation and reduction sequence.
Q7: Why is methanol used in the final drying step instead of water?
Methanol is used because it evaporates more readily than water at room temperature, ensuring thorough drying of the copper precipitate without heat damage. Multiple methanol washes followed by extended vacuum application remove residual moisture and impurities, preparing the copper for accurate final mass measurement.