11.5
A unit cell is the smallest repeating unit of a crystal lattice. The edges are labeled a, b, and c. The angles between them are α, β, and γ.
The lattice type determines the number of atoms or formula units present inside one unit cell. This number is represented by Z. For a primitive cell, Z is 1, for a body-centered cubic cell, Z is 2, and for a face-centered cubic cell, Z is 4.
To calculate the crystal density, ρ, we need its mass and volume.
The mass of a unit cell equals Z, multiplied by the molar mass, M, and divided by Avogadro’s number, NA.
For a right-angled unit cell, the volume equals the product of its edge lengths. Now, divide the mass by its volume to get the crystal density of the unit cell.
If molar mass is given in grams per mole, and the edge lengths are in centimeters, the density is reported in grams per cubic centimeter.
So, crystal density depends on the number of particles inside the unit cell and the unit cell dimensions.
The crystal lattice structure of a material allows us to determine how many molecules exist in its unit cell. With this information, alongside the unit-cell parameters - three distance parameters (a, b, c) and three angular parameters (α, β, γ).
Density (ρ) = (Z × M) / (a × b × c × NA)
where:
For a simple cubic lattice, atoms are located only at the 8 corners of the cube. Each corner atom is shared by 8 neighboring unit cells, so each contributes 1/8 to a single unit cell.
Z = 8 × (1/8) = 1
For a body-centered cubic lattice, 8 atoms are located at the corners, and 1 atom is present at the center of the cube. Each corner atom is shared by 8 neighboring unit cells, so each atom at the corner contributes 1/8 to a single unit cell. The center atom belongs entirely to the unit cell. So,
Z = (8 × 1/8) + 1 = 2
For a face-centered cubic lattice, 8 atoms are located at the corners, and 6 atoms are present on the faces of the cube. Each corner atom is shared by 8 neighboring unit cells, so each atom at the corner contributes 1/8 to a single unit cell. The atoms at the center of the faces contribute ½ to a single unit cell. So,
Z = (8 × 1/8) + (6 × ½) = 4
The density of solids is expressed in grams per milliliter (g/mL) or grams per cubic centimeter (g/cm³), since 1 milliliter equals 1 cubic centimeter.
A unit cell is the smallest repeating unit of a crystal lattice. The edges are labeled a, b, and c. The angles between them are α, β, and γ.
The lattice type determines the number of atoms or formula units present inside one unit cell. This number is represented by Z. For a primitive cell, Z is 1, for a body-centered cubic cell, Z is 2, and for a face-centered cubic cell, Z is 4.
To calculate the crystal density, ρ, we need its mass and volume.
The mass of a unit cell equals Z, multiplied by the molar mass, M, and divided by Avogadro’s number, NA.
For a right-angled unit cell, the volume equals the product of its edge lengths. Now, divide the mass by its volume to get the crystal density of the unit cell.
If molar mass is given in grams per mole, and the edge lengths are in centimeters, the density is reported in grams per cubic centimeter.
So, crystal density depends on the number of particles inside the unit cell and the unit cell dimensions.
From Chapter 11:
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