Question 1

What is Robinson annulation and what does it produce?

Accepted Answer

Robinson annulation is a base-catalyzed reaction that synthesizes 2-cyclohexenone derivatives from 1,3-dicarbonyl donors and α,β-unsaturated carbonyl acceptors. The reaction produces a six-membered ring with three new C–C bonds: two σ bonds and one π bond. Named after Sir Robert Robinson, this versatile ring-forming transformation is widely used in organic synthesis.

Question 2

How does Michael addition initiate the Robinson annulation mechanism?

Accepted Answer

Michael addition begins when a base deprotonates the acidic hydrogen in the 1,3-dicarbonyl donor, generating an enolate ion. This enolate acts as a nucleophile and undergoes conjugate addition to the α,β-unsaturated carbonyl acceptor. Protonation of the resulting anionic species forms the Michael adduct, which then proceeds to the intramolecular aldol condensation stage.

Question 3

What happens during the intramolecular aldol condensation step?

Accepted Answer

Following Michael addition, the base abstracts an appropriate α proton from the adduct to form a second enolate ion. This enolate undergoes intramolecular attack on the carbonyl carbon, forming a cyclic alkoxy intermediate. Subsequent protonation and dehydration yield the final annulated product with the characteristic double bond at the ring closure position.

Question 4

What types of starting materials work as donors in Robinson annulation?

Accepted Answer

Robinson annulation uses 1,3-dicarbonyl compounds as donors, including cyclic diketones, β-ketoesters, and β-diketones. These donors possess acidic α hydrogens that are easily deprotonated by base to form enolate ions. The presence of two electron-withdrawing carbonyl groups activates these hydrogens, making them suitable nucleophilic partners for the Michael addition step.

Question 5

How many new carbon-carbon bonds form in Robinson annulation?

Accepted Answer

Robinson annulation creates three new C–C bonds to form the six-membered ring. Two of these bonds are σ bonds formed during the Michael addition and aldol condensation steps, while the third is a π bond generated during the final dehydration. This efficient bond-forming process makes Robinson annulation a powerful synthetic tool for constructing cyclohexenone derivatives.

Question 6

Why is dehydration necessary in the final step of Robinson annulation?

Accepted Answer

Dehydration converts the cyclic alkoxy intermediate into the final annulated product by removing water. This step generates the characteristic double bond at the ring closure position, producing the α,β-unsaturated ketone (2-cyclohexenone derivative). The dehydration is essential for achieving the thermodynamically stable, conjugated enone product that defines the Robinson annulation outcome.

Question 7

What is the relationship between the donor and acceptor carbons in Robinson annulation?

Accepted Answer

In Robinson annulation, the α carbon of the 1,3-dicarbonyl donor bonds to the β carbon of the α,β-unsaturated carbonyl acceptor via Michael addition. This regioselective conjugate addition positions the enolate nucleophile at the β carbon, which is activated by the adjacent carbonyl group. This specific connectivity enables the subsequent intramolecular aldol condensation to form the six-membered ring.

Michael Ekleme ve Aldol Yoğunlaştırma yoluyla Sikloheksenonlar: Robinson Annülasyonu

Browse More Videos