6.8
Rasyonel olmayan fonksiyonları içeren integraller, özellikle integrandda köklü ifadeler yer aldığında, standart tekniklerle değerlendirmeyi çoğu zaman…
Rasyonel olmayan bir fonksiyona sahip bir integralin standart yöntemlerle değerlendirilmesi zordur.
Doğrusal kütle yoğunluğu sabit doğrusal yoğunluk, karakteristik uzunluk ve sol taraftan uzaklık olarak verilen bir çubuk düşünün.
Amaç, çubuk kütlesini bulmaktır; bu da bu yoğunluk fonksiyonunun çubuk uzunluğu boyunca entegre edilmesini gerektirir.
Küp kökleri integrali karmaşıklaştırır, bu yüzden rasyonel bir ikame faydalı olur.
X'in küp köküne eşit u olarak tanımlanan yeni bir u değişkeni getirildiğinde, ifade rasyonel bir forma dönüştürülür. Bundan x, u'nun küpü olarak alınabilir ve diferansiyel dx buna göre takip eder. Entegrasyon sınırları yeni değişkene uyacak şekilde ayarlanır.
Bu ifadeleri integrale koyduklarında, tamamen u cinsinden yazılmış bir denklem elde edilir. Varsayımlar yapıldıktan sonra, integral basit bir polinom formuna sabitleşir.
Bu dönüştürülmüş integral daha yönetilebilirdir ve polinom uzun bölme, ortaya çıkan rasyonel fonksiyonu basitleştirmeye yardımcı olur.
İfadeyi u cinsinden yeniden yazdıktan sonra, güncellenmiş limitlerle integrali değerlendirirken, çubuğun toplam kütlesi verilir.
Bu şekilde, integral rasyonelleştirici ikame kullanılarak çözülür.
View the full transcript and gain access to JoVE Core videos
Q1: What is a rationalizing substitution and when should you use it?
A rationalizing substitution converts integrals with non-rational functions, particularly those containing radicals, into rational forms that are easier to evaluate. When cube roots or other radicals complicate the integrand, introducing a new variable defined as that radical simplifies the expression into a polynomial or rational function suitable for standard integration techniques.
Q2: How do you set up a rationalizing substitution for an integral with cube roots?
Define a new variable u as the cube root of the original variable. Express the original variable as a power of u, then rewrite the differential dx in terms of du. Adjust the integration limits to reflect the new variable. Substitute these expressions into the integral to transform it entirely into terms of u, creating a rational function.
Q3: Why does rationalizing substitution work for integrals with radicals?
Radicals create non-rational integrands that resist standard integration methods. By substituting a new variable equal to the radical expression, you eliminate the radical and convert the integrand into a rational or polynomial form. This transformation allows you to apply algebraic techniques like polynomial long division to simplify and integrate the resulting expression.
Q4: What role does polynomial long division play in rationalizing substitution?
After substitution, the transformed integral often yields a rational function that requires simplification. Polynomial long division separates this rational function into simpler, more manageable terms that are straightforward to integrate individually. This algebraic step is essential for breaking down complex expressions into integrable components.
Q5: How do you adjust integration limits when using a rationalizing substitution?
When you introduce a new variable u, you must convert the original limits of integration to match the new variable. If the original limits are a and b for the variable x, substitute these values into the relationship between u and x to find the new limits. This ensures the definite integral evaluates over the correct region in the transformed variable.
Q6: Can you apply rationalizing substitution to find physical quantities like mass?
Yes. For a rod with linear mass density involving radicals, rationalizing substitution transforms the density function into an integrable form. After substitution and simplification, evaluating the transformed integral with updated limits yields the total mass. This demonstrates how rationalizing substitution solves real-world integration problems involving non-rational functions.
Q7: How does rationalizing substitution relate to other integration techniques?
Rationalizing substitution converts non-rational integrands into rational forms, which can then be handled using integration of rational functions using partial fractions or other algebraic methods. It serves as a preprocessing step that transforms difficult integrals into standard forms amenable to established integration techniques.