16.8
Electrophilic Addition of HX to 1,3-Butadiene: Thermodynamic vs Kinetic Control
The addition of a hydrogen halide to 1,3-butadiene gives a mixture of 1,2- and 1,4-adducts. Since more substituted alkenes are more stable, the 1,4-ad…
Recall that the addition of HBr to 1,3-butadiene gives 1,2- and 1,4-addition products.
The product ratio varies with temperature, with the 1,2-adduct dominating at low temperatures and the 1,4-adduct dominating at high temperatures. But why?
Let's examine the energy diagram.
The first step of the mechanism involves protonation of the diene to form a resonance-stabilized allylic cation and a bromide anion.
Next, the carbocation can pass through two different transition states to form the two products.
The transition state for the 1,2-adduct bears a positive charge on a secondary carbon, rendering it more stable and lower in energy.
Consequently, the 1,2-adduct is formed faster and is called the kinetic product. In comparison, the 1,4-adduct is more stable and is known as the thermodynamic product.
At low temperatures, the reaction is irreversible, and the product distribution depends on the relative rates. So, the 1,2-adduct dominates.
At elevated temperatures, the reaction becomes reversible. There is sufficient energy for the 1,2-adduct to ionize back to the carbocation and form the more stable 1,4-adduct as the major product.
View the full transcript and gain access to JoVE Core videos
Q1: Why does HBr addition to 1,3-butadiene produce different products at different temperatures?
Temperature controls whether the reaction is kinetically or thermodynamically controlled. At low temperatures, the reaction is irreversible, and the 1,2-adduct forms faster via a lower-energy transition state, making it the kinetic product. At high temperatures, sufficient energy allows the 1,2-adduct to revert to the carbocation intermediate, which then forms the more stable 1,4-adduct as the thermodynamic product.
Q2: What is the kinetic product in HBr addition to 1,3-butadiene?
The 1,2-adduct is the kinetic product because it forms faster at low temperatures. The transition state leading to the 1,2-adduct has a positive charge on a secondary carbon, making it more stable and lower in energy than the transition state for the 1,4-adduct. This kinetic advantage dominates when the reaction is irreversible.
Q3: How does the reaction mechanism explain the formation of both 1,2- and 1,4-adducts?
The mechanism begins with protonation of the diene to form a resonance-stabilized allylic cation and bromide anion. The carbocation intermediate can then pass through two different transition states. One pathway leads to the 1,2-adduct, while the other produces the 1,4-adduct. The relative rates and stabilities of these pathways determine which product predominates.
Q4: Why is the 1,4-adduct more stable than the 1,2-adduct?
The 1,4-adduct is more substituted, making it thermodynamically more stable. More substituted alkenes have greater stability due to better hyperconjugation and reduced steric strain. This thermodynamic advantage becomes dominant at elevated temperatures when the reaction becomes reversible and products reach equilibrium.
Q5: What does thermodynamic control mean in the context of this reaction?
Thermodynamic control occurs at high temperatures when products coexist in equilibrium. Under these conditions, the product distribution depends on the relative stabilities of the products rather than their formation rates. The more stable 1,4-adduct predominates because the system has sufficient energy to reach the most stable state.
Q6: What is kinetic control in the HBr addition to 1,3-butadiene?
Kinetic control occurs at low temperatures when the reaction is irreversible and products do not reach equilibrium. Under these conditions, the product distribution depends on the relative rates of formation rather than product stability. The 1,2-adduct dominates because it forms faster through a lower-energy transition state.
Q7: How does reversibility affect product distribution in this reaction?
At low temperatures, the reaction is irreversible, so the faster-forming 1,2-adduct accumulates as the major product. At elevated temperatures, the reaction becomes reversible, allowing the 1,2-adduct to ionize back to the carbocation intermediate. This enables formation of the more stable 1,4-adduct, which becomes the major product at equilibrium.