15.11
An object in a gravitational field experiences acceleration due to the gravitational force.
Using a physical pendulum, the value of acceleration due to gravity can be measured.
Consider a uniform rod of length L and mass m suspended from one end. The distance between the pivot point and the rod's center of mass is half the rod's length.
Recall the equation for the rotational inertia of a rod, rotating about a perpendicular axis through its center of mass.
Using the parallel-axis theorem, the rotational inertia about a perpendicular axis through one end of the rod is determined.
Recall the time period of the physical pendulum. Squaring both sides and substituting the value of the distance between the pivot point and the center of mass and the moment of inertia, the formula for the acceleration due to gravity is determined.
If the length of the rod is one meter and it has a time period of 1.64 seconds, the value of g is calculated to be 9.8 meters per second square.
Consider a coffee mug hanging on a hook in a pantry. If the mug gets knocked, it oscillates back and forth like a pendulum until the oscillations die…
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