10.10
A power series provides an alternative representation of mathematical functions that converge only when the inputs remain within a specific range.
Depending on the series, there are three cases of convergence. The series might converge only at its center, or for every real number, or for a finite range.
This range is called the interval of convergence. The radius of convergence is the fixed distance R from the center of the series to the boundary of that interval.
Consider the function one over one minus x with its power series centered at zero.
Applying the Ratio Test gives the interval of convergence. So the series converges for the values between negative one and one. Here, the distance from the center to the boundary is one, giving a radius of convergence of one.
However, the Ratio Test is inconclusive at the boundaries. These endpoints must be checked separately.
At x equals one, the series diverges. At x equals negative one, the series oscillates and does not converge. Therefore, the interval of convergence excludes both endpoints and is between negative one and one, where the power series represents the function.
A power series is a mathematical representation of a function as an infinite sum of terms involving powers of a variable. Such series converge only for specific input values, making it essential to determine the range over which the series produces valid results. This leads to the concepts of radius and interval of convergence, which define where the series behaves meaningfully.
The radius of convergence describes the distance from the center within which the power series converges. For a general power series centered at a, this can be written as:
\begin{equation*}\sum\limits_{n=0}^{\infty} c_n (x - a)^n\end{equation*}
A standard method to determine this radius is the ratio test. The limit of the ratio of consecutive terms is:
\begin{equation*}L = \lim_{n \to \infty} \left| \jfrac{c_{n+1}(x - a)^{n+1}}{c_n (x - a)^n} \right|\end{equation*}
This simplifies to:
\begin{equation*}L = |x - a| \lim_{n \to \infty} \left| \jfrac{c_{n+1}}{c_n} \right|\end{equation*}
For convergence, the condition L < 1 must hold, which gives:
\begin{equation*}|x - a| \lim_{n \to \infty} \left| \jfrac{c_{n+1}}{c_n} \right|<1\end{equation*}
Rearranging this inequality yields the radius of convergence:
\begin{equation*}R = \lim_{n \to \infty} \left| \frac{c_n}{c_{n+1}} \right|\end{equation*}
The interval of convergence is the set of all real values of x that satisfy:
\begin{equation*}|x-a|<R\end{equation*}
This defines the open interval (a - R, a + R). However, the endpoints x = a ± R must be tested separately, since the ratio test is inconclusive at these boundary points.
A power series provides an alternative representation of mathematical functions that converge only when the inputs remain within a specific range.
Depending on the series, there are three cases of convergence. The series might converge only at its center, or for every real number, or for a finite range.
This range is called the interval of convergence. The radius of convergence is the fixed distance R from the center of the series to the boundary of that interval.
Consider the function one over one minus x with its power series centered at zero.
Applying the Ratio Test gives the interval of convergence. So the series converges for the values between negative one and one. Here, the distance from the center to the boundary is one, giving a radius of convergence of one.
However, the Ratio Test is inconclusive at the boundaries. These endpoints must be checked separately.
At x equals one, the series diverges. At x equals negative one, the series oscillates and does not converge. Therefore, the interval of convergence excludes both endpoints and is between negative one and one, where the power series represents the function.
From Chapter 10:
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