14.3
A double integral finds the total accumulation of a function over a region. It is evaluated using an iterated integral, which expresses the double integral as two single integrals.
For a function over a rectangle in the xy-plane, holding x constant means slicing the region perpendicular to the x-axis and integrating with respect to y. This result is now a function of x, and integrating it with respect to x gives the total accumulation. This process also works in reverse: first along x, then y.
Fubini’s Theorem governs this process. It states that for a continuous function on a rectangle, both orders of integration give the same result.
This concept applies to real-world problems, such as finding the mass of a thin sheet with variable density.
In this case, integrating the density with respect to y gives the mass of a thin strip. Integrating these strip masses with respect to x gives the total mass.
Similarly, integrating with respect to x first and then y gives the same value. Fubini’s Theorem ensures that either order gives the same result, so the order of integration that makes the calculation easier can be chosen.
A double integral generalizes the concept of a single-variable integral to functions of two variables, enabling the computation of the volume beneath a surface z = f(x, y) over a planar region R . For a rectangular region defined by a ≤ x ≤ b and c ≤ y ≤ d, and for functions continuous on this domain, the double integral can be evaluated as an iterated integral. This approach simplifies computation by reducing the problem to successive integrations with respect to one variable at a time.
Iterated Integration and Cross-sectional Area
Holding one variable constant during integration yields a cross-sectional area function. For instance, fixing x and integrating f(x, y) with respect to y over the interval [c, d] defines the function
\begin{equation*}A(x) = \int_{c}^{d} f(x,y)\, dy\end{equation*}
which represents the area of a vertical slice through the solid at position x. The total volume under the surface is then obtained by integrating this area along the x-axis:
\begin{equation*}\iint_{R} f(x,y)\, dA = \int_{a}^{b} A(x)\, dx = \int_{a}^{b} \int_{c}^{d} f(x,y)\, dy\, dx\end{equation*}
A similar argument applies when integrating first with respect to x and then with respect to y, using horizontal cross-sections.
Fubini’s Theorem
Fubini’s Theorem formalizes the validity of iterated integration. If f is continuous on a rectangular region R, then the double integral over R can be computed as:
\begin{equation*}\iint_{R} f(x,y)\, dA = \int_{a}^{b} \int_{c}^{d} f(x,y)\, dy\, dx = \int_{c}^{d} \int_{a}^{b} f(x,y)\, dx\, dy\end{equation*}
This result ensures that the order of integration does not affect the value of the integral, providing flexibility in evaluating volumes and other quantities such as mass when density varies over a planar region.
A double integral finds the total accumulation of a function over a region. It is evaluated using an iterated integral, which expresses the double integral as two single integrals.
For a function over a rectangle in the xy-plane, holding x constant means slicing the region perpendicular to the x-axis and integrating with respect to y. This result is now a function of x, and integrating it with respect to x gives the total accumulation. This process also works in reverse: first along x, then y.
Fubini’s Theorem governs this process. It states that for a continuous function on a rectangle, both orders of integration give the same result.
This concept applies to real-world problems, such as finding the mass of a thin sheet with variable density.
In this case, integrating the density with respect to y gives the mass of a thin strip. Integrating these strip masses with respect to x gives the total mass.
Similarly, integrating with respect to x first and then y gives the same value. Fubini’s Theorem ensures that either order gives the same result, so the order of integration that makes the calculation easier can be chosen.
From Chapter 14:
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