14.10
Triple integrals over general regions describe accumulation across a bounded solid in three-dimensional space. The region E may have curved or irregular boundaries, so a systematic way is needed to define the bounds.
To define the integral over E, the solid is placed inside a larger rectangular box. A new function matches the original function inside E and is zero outside the solid. This defines the triple integral over E using the surrounding box. But for practical evaluation, the solid can be described using vertical slices.
A practical example is estimating the amount of ore in an underground deposit whose top and bottom surfaces are given by two functions.
The projection of this deposit onto the horizontal plane forms a base region, D. Each point in D gives a vertical segment through the solid, from the lower surface to the upper surface.
The triple integral is then evaluated as an iterated integral using vertical slices. In the inner integral, values are added along the vertical segments. These totals are then added over the base region D.
So, the triple integral gives the total amount of ore within the solid.
Triple integrals over general bounded regions extend the concept of double integrals from planar domains to three-dimensional solids. A solid region E in space is commonly enclosed within a rectangular box B, and a continuous function f(x, y, z) is integrated over the region by defining F such that it coincides with f on E and is zero outside the solid. The triple integral is therefore expressed as
\begin{equation*}\iiint_E f(x,y,z) dV \end{equation*}
The existence of the integral requires that f be continuous and that the boundary of E be sufficiently smooth. Similar to double integrals, the evaluation of triple integrals depends strongly on the geometric description of the region.
A common class of solids is the type I region, where the variable z is bounded between two continuous surfaces:
\begin{equation*}E=\{(x,y,z)\mid (x,y)\in D; u_1(x,y)\le z\le u_2(x,y)\}\end{equation*}
Here, D represents the projection of the solid onto the xy-plane. The lower boundary of the solid is given by z = u1(x, y), while the upper boundary is described by z = u2(x, y). In this case, the triple integral can be rewritten as an iterated integral:
\begin{equation*}\iiint_E f(x,y,z)\, dV=\iint_D\left[\int_{u_1(x,y)}^{u_2(x,y)}f(x,y,z)\, dz\right] dA\end{equation*}
If the projection D is a type I plane region,
\begin{equation*}a\le x\le b,\qquad g_1(x)\le y\le g_2(x)\end{equation*}
The integral becomes
\begin{equation*}\int_a^b\int_{g_1(x)}^{g_2(x)}\int_{u_1(x,y)}^{u_2(x,y)}f(x,y,z) dz\, dy\, dx\end{equation*}
Alternatively, when D is a type II plane region described by
\begin{equation*}c\le y\le d,\qquad h_1(y)\le x\le h_2(y)\end{equation*}
The order of integration changes accordingly:
\begin{equation*}\int_c^d\int_{h_1(y)}^{h_2(y)}\int_{u_1(x,y)}^{u_2(x,y)}f(x,y,z) dz\, dx\, dy\end{equation*}
These representations provide flexible methods for evaluating integrals over complex three-dimensional solids.
Triple integrals over general regions describe accumulation across a bounded solid in three-dimensional space. The region E may have curved or irregular boundaries, so a systematic way is needed to define the bounds.
To define the integral over E, the solid is placed inside a larger rectangular box. A new function matches the original function inside E and is zero outside the solid. This defines the triple integral over E using the surrounding box. But for practical evaluation, the solid can be described using vertical slices.
A practical example is estimating the amount of ore in an underground deposit whose top and bottom surfaces are given by two functions.
The projection of this deposit onto the horizontal plane forms a base region, D. Each point in D gives a vertical segment through the solid, from the lower surface to the upper surface.
The triple integral is then evaluated as an iterated integral using vertical slices. In the inner integral, values are added along the vertical segments. These totals are then added over the base region D.
So, the triple integral gives the total amount of ore within the solid.
From Chapter 14:
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