Question 1

Why don't unactivated halobenzenes react with nucleophiles under normal conditions?

Accepted Answer

Unactivated halobenzenes lack electron-withdrawing groups that would activate the aromatic ring toward nucleophilic attack. The strong carbon-halogen bond and the aromatic ring's stability make nucleophilic displacement unfavorable at ordinary temperatures and pressures. Extreme conditions are required to overcome this barrier and enable substitution.

Question 2

What is the Dow process and how does it convert chlorobenzene to phenol?

Accepted Answer

The Dow process converts chlorobenzene to phenol using dilute aqueous sodium hydroxide at 350°C under high pressure. The hydroxyl group displaces the chloro group through an elimination-addition mechanism. After the reaction generates sodium phenoxide, subsequent acidification produces phenol as the final product.

Question 3

What is a benzyne intermediate and how does it form in the Dow process?

Accepted Answer

A benzyne intermediate is a highly reactive aromatic species formed when the chloride ion is eliminated from chlorobenzene. The hydroxide ion abstracts a proton adjacent to the leaving group, generating a carbanion that facilitates chloride elimination. This triple-bonded intermediate is unstable and immediately reacts with the aqueous base to form the final product.

Question 4

What mechanism does the Dow process follow to produce phenol?

Accepted Answer

The Dow process follows an elimination-addition mechanism involving a benzyne intermediate. The elimination step occurs when hydroxide abstracts a proton adjacent to chlorine, creating a carbanion and eliminating chloride to form benzyne. The benzyne then undergoes nucleophilic aromatic substitution elimination-addition with the base, followed by acid workup to yield phenol.

Question 5

Why are extreme temperature and pressure conditions necessary for the Dow process?

Accepted Answer

Extreme conditions are necessary because unactivated aryl halides are inherently unreactive toward nucleophiles. The high temperature (350°C) and pressure provide sufficient energy to overcome the activation barrier for breaking the strong carbon-chlorine bond and generating the reactive benzyne intermediate. These drastic conditions enable the substitution reaction to proceed efficiently.

Question 6

What is the role of acidification in the final step of the Dow process?

Accepted Answer

Acidification converts sodium phenoxide, the intermediate product formed when benzyne reacts with aqueous base, into phenol. The acid protonates the phenoxide anion, displacing the sodium counterion and yielding the neutral phenol product. This workup step is essential for isolating the desired organic product from the aqueous reaction mixture.

Question 7

How does the hydroxide ion initiate the elimination step in the Dow process?

Accepted Answer

The hydroxide ion acts as a strong base that abstracts a proton from the carbon adjacent to the chlorine leaving group. This abstraction generates a carbanion intermediate, which destabilizes the aromatic system and facilitates elimination of the chloride ion. The resulting benzyne intermediate is then attacked by the nucleophilic base to complete the substitution.

הידרוליזה של כלור-בנזן לפנול: תהליך Dow

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﻿הידרוליזה של כלור-בנזן לפנול: תהליך Dow

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הידרוליזה של כלור-בנזן לפנול: תהליך Dow