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Q1: Why are terminal alkynes more acidic than alkanes and alkenes?
Terminal alkynes are more acidic because they form more stable carbanions upon deprotonation. The stability depends on the hybridization of the orbital holding the lone pair: sp3 orbitals in alkanes have 25% s character, sp2 orbitals in alkenes have 33%, and sp orbitals in alkynes have 50%. Since s orbitals are closer to the nucleus, higher s character stabilizes the negative charge, making acetylide anions exceptionally stable and readily formed.
Q2: What is the pKa difference between acetylene and ethane?
Acetylene has a pKa of 25, while ethane has a pKa of 51, resulting in a 26-unit difference. This means acetylene is 10^26 times more acidic than ethane. Similarly, acetylene is 10^19 times more acidic than ethylene, which has a pKa of 44. These dramatic differences illustrate how hybridization profoundly affects hydrocarbon acidity.
Q3: How do you choose a suitable base to deprotonate terminal alkynes?
For successful deprotonation, the base's conjugate acid must have a pKa at least 10 units higher than the terminal alkyne's pKa of 25, meaning the conjugate acid needs a pKa of at least 35. Sodium amide works because ammonia has a pKa greater than 35, favoring acetylide formation. Sodium hydroxide fails because water's pKa is below 25, shifting equilibrium toward reactants.
Q4: What is an acetylide ion and how is it formed?
An acetylide ion is a negatively charged carbon species formed when a terminal alkyne is deprotonated by a strong base. The suffix '-ide' indicates the negative charge. With sodium amide as the base, terminal alkynes form sodium acetylide and ammonia. Acetylide ions are stabilized by the sp orbital's 50% s character, making them highly stable intermediates for subsequent reactions.
Q5: Why does sodium hydroxide fail to deprotonate terminal alkynes?
Sodium hydroxide cannot deprotonate terminal alkynes because water, its conjugate acid, has a pKa less than 25. According to acid-base equilibrium principles, reactions favor formation of weaker acids and bases. Since water is a stronger acid than the terminal alkyne, the equilibrium shifts toward reactants, preventing acetylide formation.
Q6: What bases are commonly used to form acetylide ions?
Common bases for acetylide formation include sodium amide, sodium hydride, butyllithium, and lithium diisopropylamide (LDA). All have conjugate acids with pKa values exceeding 35, satisfying the requirement for effective deprotonation. These strong bases are essential for synthesizing organometallic compounds through preparation of alkynes alkylation reaction pathways.
Q7: How does the s character of hybrid orbitals affect carbanion stability?
Carbanion stability increases with higher s character in the hybrid orbital because s orbitals are closer to the positively charged nucleus, creating stronger electrostatic attraction for the lone pair electrons. Ethane's sp3 orbital (25% s character) produces unstable carbanions, ethylene's sp2 orbital (33%) produces more stable ones, and acetylene's sp orbital (50%) produces the most stable acetylide anions.
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