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10.6:

Hybridisatie van Atomaire Orbitalen I

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JoVE Core Chemistry
Hybridization of Atomic Orbitals I

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s-en p-orbitalen die elkaar overlappen om covalente bindingen te vormen, kunnen niet de verschillende moleculaire vormen in het VSEPR-model opleveren. De valentiebindingstheorie helpt deze moleculaire geometrie te verklaren door de hybridisatie of menging van atomaire orbitalen. Sommige atomaire orbitalen die betrokken zijn bij het binden, recombineren om nieuwe orbitalen te vormen waarvan de vormen een hybride zijn van de originelen.Het aanvankelijke aantal atomaire orbitalen en het aantal gegenereerde hybride orbitalen is altijd hetzelfde. Berylliumfluoride is een lineair molecuul. Het berylliumatoom heeft twee valentie-elektronen die in zijn 2s-orbitaal in de grondtoestand worden aangetroffen.De s-orbitaal vermengt zich met een van de lege p-orbitalen om orbitalen te creëren die ongepaarde elektronen bevatten die beschikbaar zijn voor binding. Dit laat twee niet-gehybridiseerde p-orbitalen over en produceert twee sp-hybride orbitalen, genoemd naar de oorspronkelijke atomaire orbitalen. De hybride orbitalen hebben een andere vorm dan hun samenstellende atomaire orbitalen met één lob die aanzienlijk groter is dan de andere.De kansdichtheid van de elektronen is dus sterk geconcentreerd in een directionele lob, wat leidt tot een effectievere overlap met de orbitalen van andere atomen. Voor de duidelijkheid worden deze orbitalen vaak weergegeven zonder de kleine lobben. De halfgevulde hybride orbitalen ondergaan end-to-end overlapping met orbitalen van de fluoratomen om twee identieke covalente bindingen te vormen die ook bekend staan als sigma-bindingen.Daarom vertoont berylliumfluoride sp-hybridisatie, is het lineair en heeft het een bindingshoek van 180 graden. De trigonale vlakke geometrie boortrihydride kan worden verklaard door sp^2 hybridisatie. Borium heeft één 2s en drie 2p valentie-orbitalen en drie valentie-elektronen.Drie van deze orbitalen, één s en twee p-orbitalen, mengen zich om een set van drie sp^2-orbitalen te produceren, die elk één ongepaard elektron bevatten, en één 2p-orbitaal blijft ongehybridiseerd. Elk van deze overlapt met een 1s-orbitaal van een waterstofatoom om drie sigma-bindingen te vormen. Een molecuul met sp^2-hybridisatie heeft een trigonale vlakke geometrie met bindingshoeken van 120 graden.sp^3 hybride orbitalen vormen de tetraëdrische vorm van een methaanmolecuul. Het koolstofatoom heeft vier valentie-elektronen. Het mengen van de 2s en drie 2p-orbitalen genereert vier equivalente sp^3 hybride orbitalen die elk één ongepaard elektron kunnen bevatten.De hybride orbitalen verkregen door sp^3-hybridisatie overlappen met de 1s-orbitalen van de waterstofatomen om een methaanmolecuul te produceren met een tetraëdrische geometrie en een bindingshoek van 109, 5 graden.

10.6:

Hybridisatie van Atomaire Orbitalen I

The mathematical expression known as the wave function, ψ, contains information about each orbital and the wavelike properties of electrons in an isolated atom. When atoms are bound together in a molecule, the wave functions combine to produce new mathematical descriptions that have different shapes. This process of combining the wave functions for atomic orbitals is called hybridization and is mathematically accomplished by the linear combination of atomic orbitals. The new orbitals that result are called hybrid orbitals.

Understanding Atomic Orbital Hybridization

The following ideas are important in understanding hybridization:

  1. Hybrid orbitals do not exist in isolated atoms. They are formed only in covalently bonded atoms.
  2. Hybrid orbitals have shapes and orientations that are very different from those of the atomic orbitals in isolated atoms.
  3. A set of hybrid orbitals is generated by combining atomic orbitals. The number of hybrid orbitals in a set is equal to the number of atomic orbitals that were combined to produce the set.
  4. All orbitals in a set of hybrid orbitals are equivalent in shape and energy.
  5. The type of hybrid orbitals formed in a bonded atom depends on its electron-pair geometry, as predicted by the VSEPR theory.
  6. Hybrid orbitals overlap to form σ bonds. Unhybridized orbitals overlap to form π bonds.

In the following sections, we shall discuss the common types of hybrid orbitals.

sp Hybridization

The beryllium atom in a gaseous BeCl2 molecule is an example of a central atom with no lone pairs of electrons in a linear arrangement of three atoms. There are two regions of valence electron density in the BeCl2 molecule that correspond to the two covalent Be–Cl bonds. To accommodate these two electron domains, two of the Be atom’s four valence orbitals will mix to yield two hybrid orbitals. This hybridization process involves the mixing of the valence s orbital with one of the valence p orbitals to yield two equivalent sp hybrid orbitals that are oriented in a linear geometry. The set of sp orbitals appears similar in shape to the original p orbital, but there is an important difference. The number of atomic orbitals combined always equals the number of hybrid orbitals formed. The p orbital is one orbital that can hold up to two electrons. The sp set is two equivalent orbitals that point 180° from each other. The two electrons that were originally in the s orbital are now distributed to the two sp orbitals, which are half-filled. In gaseous BeCl2, these half-filled hybrid orbitals will overlap with orbitals from the chlorine atoms to form two identical σ bonds.

When atomic orbitals hybridize, the valence electrons occupy the newly created orbitals. The Be atom had two valence electrons, so each of the sp orbitals gets one of these electrons. Each of these electrons pairs up with the unpaired electron on a chlorine atom when a hybrid orbital and a chlorine orbital overlap during the formation of the Be–Cl bonds.

Any central atom surrounded by just two regions of valence electron density in a molecule will exhibit sp hybridization. Other examples include the mercury atom in the linear HgCl2 molecule, the zinc atom in Zn(CH3)2, which contains a linear C–Zn–C arrangement, and the carbon atoms in HCCH and CO2.

sp2 Hybridization

The valence orbitals of a central atom surrounded by three regions of electron density consist of a set of three sp2 hybrid orbitals and one unhybridized p orbital. This arrangement results from sp2 hybridization, the mixing of one s orbital and two p orbitals to produce three identical hybrid orbitals oriented in a trigonal planar geometry.

The observed structure of the borane molecule, BH3, suggests sp2 hybridization for boron in this compound. The molecule is trigonal planar, and the boron atom is involved in three bonds to hydrogen atoms. The three valence electrons of the boron atom in the three sp2 hybrid orbitals are redistributed, and each boron electron pairs with a hydrogen electron when B–H bonds form.

Any central atom surrounded by three regions of electron density will exhibit sp2 hybridization. This includes molecules with a lone pair on the central atom, such as ClNO, or molecules with two single bonds and a double bond connected to the central atom, as in formaldehyde, CH2O, and ethene, H2CCH2.

sp3 Hybridization

The valence orbitals of an atom surrounded by a tetrahedral arrangement of bonding pairs and lone pairs consist of a set of four sp3 hybrid orbitals. The hybrids result from the mixing of one s orbital and all three p orbitals, which produces four identical sp3 hybrid orbitals. Each of these hybrid orbitals points toward a different corner of a tetrahedron.

A molecule of methane, CH4, consists of a carbon atom surrounded by four hydrogen atoms at the corners of a tetrahedron. The carbon atom in methane exhibits sp3 hybridization. The four valence electrons of the carbon atom are distributed equally in the hybrid orbitals, and each carbon electron pairs with a hydrogen electron when the C–H bonds form.

In a methane molecule, the 1s orbital of each of the four hydrogen atoms overlaps with one of the four sp3 orbitals of the carbon atom to form a sigma (σ) bond. This results in the formation of four strong, equivalent covalent bonds between the carbon atom and each of the hydrogen atoms to produce the methane molecule, CH4.

An sp3 hybrid orbital can also hold a lone pair of electrons. For example, the nitrogen atom in ammonia is surrounded by three bonding pairs and a lone pair of electrons directed to the four corners of a tetrahedron. The nitrogen atom is sp3 hybridized with one hybrid orbital occupied by the lone pair.

The molecular structure of water is consistent with a tetrahedral arrangement of two lone pairs and two bonding pairs of electrons. Thus we say that the oxygen atom is sp3 hybridized, with two of the hybrid orbitals occupied by lone pairs and two by bonding pairs. Since lone pairs occupy more space than bonding pairs, structures that contain lone pairs have bond angles slightly distorted from the ideal. Perfect tetrahedral structures have angles of 109.5°, but the observed angles in ammonia (107.3°) and water (104.5°) are slightly smaller. Other examples of sp3 hybridization include CCl4, PCl3, and NCl3.

This text has been adapted from Openstax, Chemistry 2e, Section 8.2: Hybrid Atomic Orbitals.