# Plastic Deformation in Circular Shafts

JoVE 핵심
Mechanical Engineering
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JoVE 핵심 Mechanical Engineering
Plastic Deformation in Circular Shafts

### Next Video19.9: Circular Shafts – Elastoplastic Materials

When materials are subjected to stresses exceeding their yield strength, plastic deformation occurs, causing a permanent strain. In the case of circular shafts, plastic deformation changes its configuration.

An accurate assessment of plastic deformation necessitates the determination of stress distribution within the circular shaft.

If the maximum shearing stress in the material is known, then plotting a shearing-stress-strain diagram gives the corresponding maximum shearing strain.

Recall that the shearing strain varies linearly with the distance from the axis of the shaft. The relationship between shearing strain and radial distance is established by substituting the maximum shearing strain value. Further, the relationship between shearing stress and radial distance is obtained.

Using the integral relation and substituting for the elemental area and the polar moment of inertia in terms of shaft radius, the ultimate torque that causes shaft failure can be determined by maximizing the value of the material's ultimate shearing stress.

The corresponding fictitious stress is called the modulus of rupture in the torsion of the given material.

## Plastic Deformation in Circular Shafts

When materials are subjected to forces that surpass their yield strength, they undergo a process known as plastic deformation. This results in a permanent alteration or strain in their structure. This concept can be specifically applied to circular shafts, where the deformation leads to a change in its shape. The precise evaluation of this plastic deformation requires understanding the stress distribution within the circular shaft, which is achieved by calculating the maximum shearing stress in the material. Once identified, a shearing-stress-strain diagram can be plotted to reveal the maximum shearing strain. It is crucial to remember that the shearing strain has a linear relationship with the distance from the axis of the shaft.

The relationship between shearing strain and radial distance can be determined by substituting the maximum shearing strain value into this equation. Similarly, the relationship between shearing stress and radial distance can also be derived. By using the integral relation and replacing the elemental area and polar moment of inertia with the shaft radius, the ultimate torque that leads to the shaft's failure can be calculated by maximizing the material's ultimate shearing stress value. The equivalent stress derived from this calculation is often referred to as the modulus of rupture in the torsion of the given material. This term represents the maximum stress to endure before the material fails under torsion.